Confusion regarding the Boltzman distribution as it applies to paramagnetism

In summary, in a thermal physics course, the Boltzmann factor was discussed as a way to calculate quantities using probability distribution. The concept of paramagnetism was introduced, where a system of independent magnetic spins in contact with a thermal reservoir was considered. Each spin has a potential energy given by E_n = +/- μB, and the Boltzmann distribution was used to determine the fractions of spins in each state. The temperature of the magnetic material is determined by the reservoir, and thermal agitation causes a fraction of the spins to be in a higher energy state, reducing the overall magnetization. However, the thermal energy of the reservoir also partially prevents the magnetization from occurring at absolute zero. The mechanism by which thermal energy causes spins to be
  • #1
FluxPin
3
0
I'm currently in an introductory thermal physics course, and today we
learned about the Boltzmann factor and how to use it to calculate
various quantities with the corresponding probability distribution. All was going well until we got to the subject of paramagnetism.

We supposed a system of independent magnetic spins, pointing either
parallel or anti-parallel to the Magnetic field given by [itex]\vec{B}[/itex]. In other
words, there are N spins each with magnetic moment [itex]\vec{μ}[/itex] in contact with a
thermal reservoir of temperature T.

I understand that each spin has a potential energy given by
E[itex]_{n}[/itex]=[itex]\pm[/itex][itex]\vec{μ}[/itex][itex]\vec{B}[/itex] (A basic E&M result). However, I DON'T really understand how we can relate this
quantity to the Boltzmann distribution: P[itex]_{n}[/itex]= e^([itex]\frac{-E_{n}}{kT}[/itex])/Z where Z is the partition function which normalizes the distribution.

How can the thermal energy of the reservoir (kT) can be related to the
purely magnetic state of each magnetic spin? I'm clearly missing
something since this makes no sense to me. Is energy also going into
the thermal energy of these spins and we are just not considering it?
I'm quite confused by this concept and any clarification would be most
appreciated.
 
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  • #2
Think about it in the other order: the spins don't determine the reservoir, but rather the reservoir sets the temperature of the magnetic material, allowing you to calculate the magnetization. Electrons can be in two states (aligned and anti-aligned) having energies +/-E_n; the Boltzmann distribution tells you the fractions of total electrons, P_1=N_1/N and P_2=N_2/N, that are in each state. The net magnetization is then
[tex]M=N(P_1-P_2)\mu=(N_1-N_2)\mu.[/tex]
 
  • #3
I understand that the magnetic moments do not determine the reservoir. What I'm having a conceptual issue with is why the temperature of the magnetic material (which I understand is completely dependent on the reservoir) can be related to its magnetization (i.e. the probability of a moment aligning itself along the field) with the Boltzmann distribution.
marcusl said:
the reservoir sets the temperature of the magnetic material, allowing you to calculate the magnetization.
How does the temperature of the material determine its magnetization?
 
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  • #4
The temperature is not causing the magnetization, it's partially preventing it. If the temperature was absolute zero, all the dipoles would sit happily in the lower energy state and the system would be fully magnetized. Thermal agitation kicks a fraction of them to the higher energy state, reducing the magnetization.
 
  • #5
Okay, all the dipoles being in their lowest energy level at absolute zero makes. The thing I still don't get is how the thermal energy of the reservoir puts the individual dipoles into their higher energy magnetic state. That is, he mechanism by which they are "kicked" into the higher energy state.
 
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Related to Confusion regarding the Boltzman distribution as it applies to paramagnetism

What is the Boltzmann distribution?

The Boltzmann distribution is a statistical distribution that describes the probability of a particle being in a specific energy state. It is based on the principle of thermal equilibrium, where particles tend to distribute themselves in a way that maximizes entropy.

How does the Boltzmann distribution apply to paramagnetism?

In paramagnetism, the behavior of magnetic materials is described by the Boltzmann distribution. The distribution shows the probability of individual magnetic moments aligning with an external magnetic field, leading to an overall increase in magnetization.

What factors influence the Boltzmann distribution in paramagnetism?

The Boltzmann distribution in paramagnetism is influenced by temperature and energy levels of the magnetic moments. As temperature increases, the distribution shifts towards higher energy levels, resulting in a higher overall magnetization. Additionally, the strength of the external magnetic field also affects the distribution.

Why is there confusion surrounding the Boltzmann distribution in paramagnetism?

There is often confusion surrounding the Boltzmann distribution in paramagnetism because it is a complex mathematical concept that requires a strong understanding of statistical mechanics. Additionally, the application of the distribution to real-world systems can be challenging and may lead to discrepancies between theoretical predictions and experimental results.

What are the practical applications of the Boltzmann distribution in paramagnetism?

The Boltzmann distribution in paramagnetism has practical applications in a variety of fields, including materials science, chemistry, and engineering. It is used to understand and predict the behavior of magnetic materials, which is crucial for developing new technologies such as magnetic storage devices and sensors.

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