- #1
Grufey
- 30
- 0
Hello!, I was studing the conformal maps in complex analysis, I don't understand this definition:
Definition: A map [tex]f:A\rightarrow\mathbb{C}[/tex] is called conformal at [tex]z_0[/tex] if there exist a [tex]\theta\in[0,2\pi][/tex] and [tex]r>0[/tex] such that for any curve [tex]\gamma(t)[/tex] which is differentiable at [tex]t=0[/tex], for which [tex]\gamma(t) \in A[/tex] and [tex]\gamma(0)=z_0[/tex], and which satisfisfies [tex]\gamma\prime(0)\neq0[/tex] the curve [tex]\sigma(t)=f(\gamma(t))[/tex] is differentiable at [tex]t=0[/tex] and, setting [tex]u=\sigma\prime(0)[/tex] and [tex]v=\gamma\prime(0)[/tex], we have [tex]\left|u\right|=r\left|v\right|[/tex] and [tex]\arg u =\arg v + \theta (\mod 2\theta)[/tex]
I only know about the conformal maps, that the angle between the curves after the transform is equal to the before of the transformation. But I cannot find the relation, with the definition. I think that I don't undertand the definition.
Thanks
Definition: A map [tex]f:A\rightarrow\mathbb{C}[/tex] is called conformal at [tex]z_0[/tex] if there exist a [tex]\theta\in[0,2\pi][/tex] and [tex]r>0[/tex] such that for any curve [tex]\gamma(t)[/tex] which is differentiable at [tex]t=0[/tex], for which [tex]\gamma(t) \in A[/tex] and [tex]\gamma(0)=z_0[/tex], and which satisfisfies [tex]\gamma\prime(0)\neq0[/tex] the curve [tex]\sigma(t)=f(\gamma(t))[/tex] is differentiable at [tex]t=0[/tex] and, setting [tex]u=\sigma\prime(0)[/tex] and [tex]v=\gamma\prime(0)[/tex], we have [tex]\left|u\right|=r\left|v\right|[/tex] and [tex]\arg u =\arg v + \theta (\mod 2\theta)[/tex]
I only know about the conformal maps, that the angle between the curves after the transform is equal to the before of the transformation. But I cannot find the relation, with the definition. I think that I don't undertand the definition.
Thanks