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#### TheFallen018

##### Member

- Nov 9, 2017

- 45

So, my problem is with a degree 3 complex polynomial. I'm given one zero of the equation, but since it is a complex zero, I can use the conjugate too. So, I already have two of the zeros for the polynomial, and since according to the fundamental theorem of algebra, it should only have one more. Because complex roots also have a conjugate, this suggests that the root is real. However, I'm having a hard time pinning it down. I've come up with a number of answers, and one of my more recent attempts led me to think it was -1. None of these seem right.

So, here's the question.

Any help would be amazing. Thank you