Comparing SHM of Two Identical Masses on Springs

In summary, the conversation discusses the relationship between the spring constant and simple harmonic motion of two identical masses oscillating on springs. The higher the spring constant, the harder it is to compress the spring. This can affect the amplitude and frequency of the oscillation. The frequency is measured in cycles per second and can be described as higher or lower. The wavelength can also be described as longer or shorter. There is a relationship between frequency and spring constant, which can be looked up.
  • #1
SherlockIsReal
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0

Homework Statement


Compare the simple harmonic motion of two identical masses oscillating up and down on springs with different spring constants.

Homework Equations


F = -kx

The Attempt at a Solution


Okay, so I understand that the higher the spring constant, the harder it is to compress the spring. But I don't know how to relate that to the graph of harmonic motion. If the spring constant is higher , does that mean that the amplitude is lower? Or that the frequency is shorter?
 
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  • #2
SherlockIsReal said:
that the frequency is shorter?
Do have any equation relating time period and spring constant.
 
  • #3
SherlockIsReal said:
Or that the frequency is shorter?
For one thing, frequency is cycles per second (or radians per second, for angular frequency). Frequencies could be described as higher or lower; wavelengths, as longer or shorter.

How does frequency relate to spring constant? Look it up!
 

Related to Comparing SHM of Two Identical Masses on Springs

1. What is SHM and how does it relate to springs?

SHM stands for Simple Harmonic Motion, which is a type of motion where a system oscillates back and forth around a stable equilibrium point. Springs are often used to demonstrate SHM because they have a linear restoring force that follows Hooke's Law, causing the oscillations.

2. Why is it important to compare SHM of two identical masses on springs?

Comparing SHM of two identical masses on springs allows us to study the effects of different factors on the motion, such as changing the spring constant or mass. This can help us understand the principles of SHM and how it applies to other systems.

3. How do you calculate the period of oscillation for a system with two identical masses on springs?

The period of oscillation for a system with two identical masses on springs can be calculated using the equation T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. This assumes that the system is ideal and there is no friction or other external forces.

4. Can the amplitude of oscillation affect the SHM of two identical masses on springs?

Yes, the amplitude of oscillation can affect the SHM of two identical masses on springs. As the amplitude increases, the period of oscillation remains constant, but the maximum velocity and acceleration also increase. This can lead to changes in the system's behavior, such as reaching a higher maximum displacement or experiencing greater forces.

5. What factors can affect the SHM of two identical masses on springs?

The SHM of two identical masses on springs can be affected by various factors, such as the mass, spring constant, amplitude, and initial conditions (e.g. initial displacement and velocity). Other external factors, such as friction and air resistance, can also impact the motion and make it deviate from ideal SHM. Additionally, changes in the gravitational field or temperature can also affect the system's behavior.

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