- #1
Shivang kohlii
- 19
- 1
Homework Statement
A block of mass m having charge q placed on smooth horizontal table and is connected to a wall thorough an unstretched spring of constant k . A horizontal electric field E parallel to spring is switched on. Find the ampliture of the shm by the block.
Homework Equations
kx= qe
U of spring= 1/2kx[2][/SUP]
The Attempt at a Solution
Using conservation of energy and work done by field ,F = qEx
1/2kx^2 = qEx
X (amplitude ) = 2qE/x
But ans isn't this..
In answer directly the forces have been equated
qE = kx
.. I don't understand why has this equation been used to calculate amplitude when conservation of energy is used to calculate the maximum displacement of a body attached to spring when moved from equilibrium position in ?
Last edited: