Circular Motion, an object attached by a string to a motor

In summary, the student attempted to solve for the velocity of the pendulum by using the period and frequency, but was unable to find a solution.
  • #1
SDTK
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Homework Statement



A pendulum traveling at constant speed along a circular path
Determine the angle that the string makes with the vertical.

T[/B]he length of the string was measured to be 60 cm.
The period was measured to be 1.41 s
The frequency was found to be 0.709


2. Homework Equations

Is it possible to find the radius with only the Period T and frequency f?

3. The Attempt at a Solution

I believe that it should be possible to use the period and frequency to find the velocity, and from there the radius. Once I have the radius, I can find the angle.

Using:
v = 2(pi)r / T, v = 2 (pi)fr,
v = (2 x pi x radius)/period, v = 2 x pi x frequency x radius

a = v^2/r = (2(pi)f)^2r =(2(pi)/T)^2 r
a = velocity squared / radius = (2 x pi x frequency) squared x radius
= ((2 x pi) / T))squared x radius

I have tried solving for "r" and substituting the solution in order to find velocity, ... but I end up circling back the an equation with both the two unknown variables that I am trying to find, v and r.

with advanced thanks for any advise,
D.T.
 
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  • #2
How about drawing a free body diagram of the pendulum? Identify all forces acting and apply Newton's 2nd law.
 
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  • #3
Referring to the thread title, I'm not seeing where the motor comes in...
 
  • #4
gneill said:
Referring to the thread title, I'm not seeing where the motor comes in...
I'm guessing the string of the pendulum is tied to some spinning axis--driven by the motor.
 
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  • #5
Doc Al said:
I'm guessing the string of the pendulum is tied to some spinning axis--driven by the motor.
Ah. Alrighty then. :smile:
 
  • #6
Air resistance is not considered
scan0002.jpg


I understand that that force (net) = ma = (mv^2)/r
and that mass "cancels out" so Force(net) = a = v^2 / r.

Velocity is not known. Neither is the radius, or angle

(the length of the string providing the tension, the period and the frequency are known.)

I thought that I could solve for velocity, and from velocity, solve for radius, ... but am now wondering if there is enough info to so do
 
Last edited:
  • #7
Apply Newton's 2nd law to vertical and horizontal force components separately.
 
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  • #8
Doc Al said:
Apply Newton's 2nd law to vertical and horizontal force components separately.
thank you
 

Related to Circular Motion, an object attached by a string to a motor

1. What is circular motion?

Circular motion refers to the movement of an object along a circular path. In this type of motion, the object's speed and direction are constantly changing as it moves around the circle.

2. How is an object attached by a string to a motor related to circular motion?

In circular motion, an object is attached to a central point and is pulled by a force, much like an object attached by a string to a motor. The motor provides the necessary force to keep the object moving along the circular path.

3. What is the role of centripetal force in circular motion?

Centripetal force is the force that keeps an object moving in a circular path. It acts towards the center of the circle and is responsible for changing the direction of the object's velocity. In the case of an object attached by a string to a motor, the tension in the string acts as the centripetal force.

4. How does the speed of the object affect circular motion?

The speed of the object affects the amount of centripetal force needed to keep it moving in a circular path. The faster the object moves, the greater the centripetal force required. If the speed is too slow, the object will not be able to maintain the circular motion and will move off the path.

5. Can circular motion be considered as a type of uniform circular motion?

Yes, circular motion can be considered as a type of uniform circular motion if the speed of the object remains constant throughout the motion. In this case, the object moves around the circle with a constant speed and the centripetal force required to keep it moving is also constant.

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