- #1
greg_rack
Gold Member
- 363
- 79
- Homework Statement
- Write and explain the free-body-diagram of the forces acting on a cabin of a Ferris wheel, in a uniform circular motion at the instant in which it's at the same height as the wheel's pivot point.
- Relevant Equations
- Standard motion equations
Hi guys,
given the "blacker" to be the cabin under consideration,
I firstly wrote its weight force; then, my confusion started when drawing the force applied on the cabin by the structure(##F_{r}##).
I concluded it must have been both counter-acting the weight, and acting as a centripetal force... but I'm quite uncertain about it and I'd appreciate knowing if I'm correct or no.
The path I'm taking, for now, is that vertical component ##F_{ry}## must be equal to the weight, while the horizontal ##F_{rx}## to the centripetal force, resulting thus in an inclined force with respect to the standard vertical direction, pointing in the second quadrant of an ##xy## plane.
What do you think about it? Have I made any mistakes or imprecisions?
given the "blacker" to be the cabin under consideration,
I firstly wrote its weight force; then, my confusion started when drawing the force applied on the cabin by the structure(##F_{r}##).
I concluded it must have been both counter-acting the weight, and acting as a centripetal force... but I'm quite uncertain about it and I'd appreciate knowing if I'm correct or no.
The path I'm taking, for now, is that vertical component ##F_{ry}## must be equal to the weight, while the horizontal ##F_{rx}## to the centripetal force, resulting thus in an inclined force with respect to the standard vertical direction, pointing in the second quadrant of an ##xy## plane.
What do you think about it? Have I made any mistakes or imprecisions?