Charged Capacitors - Homework Equations & Attempt at Solution

In summary, the conversation discusses finding equations for total voltage across a resistor and voltages across two capacitors that are charged to different values and connected in series with a resistor. The suggested approach is to write out the differential equation for the set-up and solve it in a similar manner to the simpler case, in order to understand how to apply it to the given scenario.
  • #1
jh001
3
0

Homework Statement


A 10nF and 20nF capacitor is independently charged to respectively 40V and 50V. The positive sides of the two capacitors are connected, and a 1kΩ resistor is connected across the negative terminals. Find equations for total voltage VT(t) across the resistor and voltages across each capacitor V1(t) and V2(t)

Homework Equations


V(t)=V0e-t/RC

The Attempt at a Solution


It seems VT(0) = 50-40 = 10V.
Can we use VT(t)=V2(t)-V1(t), since the capacitors are connected positive to positive? In that case what value for R do we use for each capacitor?
 
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  • #2
There may be some law you can appeal to, but it isn't hard to work out from first principles. (I.e., obtain a differential equation for the current.)
 
  • #3
"work out from first principles" is a bit cryptic/generic and not really helpful. The equation I gave IS in effect a differential equation (well, the solution to one) Can you please elaborate?
 
  • #4
jh001 said:
"work out from first principles" is a bit cryptic/generic and not really helpful. The equation I gave IS in effect a differential equation (well, the solution to one) Can you please elaborate?
Yes, it's the solution to a differential equation, but you don't know how to apply it because the equation was for a simpler set-up. I'm proposing writing out the differential equation for the set-up in the question and solving that in the same way. You can then be confident in how to apply it here. (It turns out to be just what you might have guessed.)
 

Related to Charged Capacitors - Homework Equations & Attempt at Solution

1. What is a capacitor and how does it work?

A capacitor is an electronic component that stores electrical energy in the form of an electric field. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied to the capacitor, one plate becomes positively charged and the other becomes negatively charged, creating an electric field between them. This electric field stores the energy until it is discharged.

2. How are capacitors charged?

Capacitors can be charged in two ways: through a direct current (DC) source or through an alternating current (AC) source. In a DC circuit, the capacitor charges up to the same voltage as the source. In an AC circuit, the capacitor charges and discharges repeatedly as the AC source alternates between positive and negative voltages.

3. What is the difference between a charged and uncharged capacitor?

An uncharged capacitor has no electric charge or voltage across its plates. When a capacitor is charged, one plate becomes positively charged and the other becomes negatively charged, creating an electric field between them. This allows the capacitor to store energy, whereas an uncharged capacitor cannot.

4. What is the equation for calculating the charge on a capacitor?

The equation for calculating the charge on a capacitor is Q = CV, where Q is the charge in coulombs, C is the capacitance in farads, and V is the voltage across the capacitor. This equation is known as the capacitor equation and is used to determine the amount of charge stored on a capacitor.

5. How can I determine the capacitance of a capacitor?

The capacitance of a capacitor can be determined by the equation C = Q/V, where C is the capacitance in farads, Q is the charge in coulombs, and V is the voltage across the capacitor. Alternatively, you can also use a capacitance meter to directly measure the capacitance of a capacitor.

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