Centripetal Force, very simple.

[nothing4me]

Homework Statement

A man hanging upside down is holding a partner who weighs 475 N. Assume that the
partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.00 m/s,
what force must the man apply to his partner in the straight-down position?

Homework Equations

F=mv^2/r

The Attempt at a Solution

I just plugged in the numbers and got 1,169. Is it correct?

 

[tiny-tim]

A man hanging upside down is holding a partner who weighs 475 N. Assume that the
partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.00 m/s,
what force must the man apply to his partner in the straight-down position?
…
F=mv^2/r
…
I just plugged in the numbers and got 1,169. Is it correct?

Hi nothing4me!

That's the correct centripetal force, but you still have to deal with the gravitational force.

 

[thomate1]

I would like to point out that your calculation is correct, assuming all the given values are accurate. The formula you used, F=mv^2/r, is the equation for centripetal force, which is the force required to keep an object moving in a circular path. In this case, the man must apply a force of 1,169 N to his partner in order to maintain their circular motion with a radius of 6.50 m and a speed of 4.00 m/s. It is important to note that centripetal force is always directed towards the center of the circle, in this case, towards the ground. This force is necessary to counteract the natural tendency of the partner to move in a straight line due to inertia. Overall, this is a great example of how centripetal force plays a crucial role in many everyday activities, from amusement park rides to sports like figure skating and gymnastics.