- #1
Lukeblackhill
- 39
- 3
Poster reminded to use the standard Template for schoolwork
Dear Mates,
I was studying Newton's Laws of Motion by Berkeley's Physics Course, Vol. 1 - Chap. 3, when I came across this problem, about finding the maximum separation of the boys. In my mind, it was simply about finding the "2x", considering x to be the distance between the first boy and the position of the ball at maximum height. Working with the equations of motion for a uniform gravitational field, the task would be resumed in applying the problem's variables to the equation R = Vo²sin2θ/g. But I don't know if this interpretation of mine is wrong of if I've made mistakes in the arithmetics, but I simply can't arrive in the result presented by the own book. And without knowing what I did wrong, I'm unable to give the explanation next requested.
Ceiling height for a game of catch. Two boys "play catch" with a ball in a long hallway. The ceiling height is H, and the ball is thrown and caught at shoulder height, which we call h for each boy, If the boys are capable of throwing the ball with velocity vo, at what maximum separation can they play?
Ans. R = 4V(H - h)[vo²/2g - (H - h)]. Show that if H - h > vo²/4g, R = vo²/g. Explain the physical significance of the condition H - h > vo²/4g.
Thank you for your help,
Cheers,
Luke
I was studying Newton's Laws of Motion by Berkeley's Physics Course, Vol. 1 - Chap. 3, when I came across this problem, about finding the maximum separation of the boys. In my mind, it was simply about finding the "2x", considering x to be the distance between the first boy and the position of the ball at maximum height. Working with the equations of motion for a uniform gravitational field, the task would be resumed in applying the problem's variables to the equation R = Vo²sin2θ/g. But I don't know if this interpretation of mine is wrong of if I've made mistakes in the arithmetics, but I simply can't arrive in the result presented by the own book. And without knowing what I did wrong, I'm unable to give the explanation next requested.
Ceiling height for a game of catch. Two boys "play catch" with a ball in a long hallway. The ceiling height is H, and the ball is thrown and caught at shoulder height, which we call h for each boy, If the boys are capable of throwing the ball with velocity vo, at what maximum separation can they play?
Ans. R = 4V(H - h)[vo²/2g - (H - h)]. Show that if H - h > vo²/4g, R = vo²/g. Explain the physical significance of the condition H - h > vo²/4g.
Thank you for your help,
Cheers,
Luke