- #1
Objection
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- 0
Homework Statement
the initial velocity of a projectile is 150 m\s .the angle between the velocity vector and the trajectory at the projectile's maximum height is
a) 90
b) 45
c) zero
d) 63.1
e) 36.9
Homework Equations
Vox= vx = Vocosθ
Vy = Vosinθ-gt
Range (R) = (vo)^2*sin(2θ)/g
Maximum Height (H) = (vo)^2*(sinθ)^2/2g
The Attempt at a Solution
http://im40.gulfup.com/43qMA.jpg
in this image we can see that the angle at the maximum height is 0 but I want to get sure ?
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