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anemone
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Without the help of calculator, show that $\tan 50^{\circ}>1.18$
anemone said:Without the help of calculator, show that $\tan 50^{\circ}>1.18$
chisigma said:[sp]Considering the first eight of the McLaurin series of the function tan x...
$\displaystyle \tan x \sim x + \frac{1}{3}\ x^{3} + \frac{2}{15}\ x^{5} + \frac {17}{315}\ x^{7}\ (1)$... setting in (1) $x = \frac{5}{18}\ \pi$ You obtain... $\displaystyle \tan x \sim 1.182468$[/sp]
Kind regards
$\chi$ $\sigma$
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