- #1
pc2-brazil
- 205
- 3
Good afternoon,
This is not actually a homework question; it's for self-study. I'm reading a Calculus book, and one of its exercises asks the following:
If xnym = (x+y)n+m, show that xDxy = y (where Dxy is the derivative of y with respect to x).
The only way I could think of to get the correct result is by implicit differentiation. I tried to do implicit differentiation of the given equation, but it got me nowhere:
[tex]D_x(x^ny^m)=D_x((x+y)^{n+m})[/tex]
Applying the product rule in the left side and the chain rule in the right side:
[tex]nx^{n-1}y^m+my^{m-1}x^nD_xy=(n+m)(x+y)^{n+m-1}(1+D_xy)[/tex]
I tried to do many manipulations, but I don't see any way to get the expected result.
Could the equation given be wrong? I tried to let n = 1 and m = 1 and see what happens:
x1y1 = (x+y)1+1
xy = (x+y)²
If I implicitly differentiate it, I get:
[tex]y + xD_xy = 2(x+y)(1+D_xy)[/tex],
which, after some manipulation, becomes:
[tex]D_xy = \frac{2x+y}{-x-2y}[/tex]
This result seems to suggest that the equation given is not correct. Or am I doing something wrong?
Thank you in advance.
This is not actually a homework question; it's for self-study. I'm reading a Calculus book, and one of its exercises asks the following:
If xnym = (x+y)n+m, show that xDxy = y (where Dxy is the derivative of y with respect to x).
The only way I could think of to get the correct result is by implicit differentiation. I tried to do implicit differentiation of the given equation, but it got me nowhere:
[tex]D_x(x^ny^m)=D_x((x+y)^{n+m})[/tex]
Applying the product rule in the left side and the chain rule in the right side:
[tex]nx^{n-1}y^m+my^{m-1}x^nD_xy=(n+m)(x+y)^{n+m-1}(1+D_xy)[/tex]
I tried to do many manipulations, but I don't see any way to get the expected result.
Could the equation given be wrong? I tried to let n = 1 and m = 1 and see what happens:
x1y1 = (x+y)1+1
xy = (x+y)²
If I implicitly differentiate it, I get:
[tex]y + xD_xy = 2(x+y)(1+D_xy)[/tex],
which, after some manipulation, becomes:
[tex]D_xy = \frac{2x+y}{-x-2y}[/tex]
This result seems to suggest that the equation given is not correct. Or am I doing something wrong?
Thank you in advance.
Last edited: