- #1
chibi_lenne
- 18
- 0
Seriously, if I didn't need physics I probably wouldn't take it.I've don the work for this one problem, but then I'm not sure if it's the right formula for what I need. Here's what I have so far(the parts in bold are the work I've done)
10. An electromagnetic radiation has a frequency of 5.00 x 10^14Hz.
b) Calculate its wavelength in water.
Given: wavelength = 0.6 x 10^-6m or 600nm
Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med})
10. An electromagnetic radiation has a frequency of 5.00 x 10^14Hz.
b) Calculate its wavelength in water.
Given: wavelength = 0.6 x 10^-6m or 600nm
n = 1.33 for water
Required: wavelength(med)Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med})
therefore wavelength(vac) = (n)(wavelength{med}) and
wavelength(med) = wavelength(vac)/n
Solution: wavelength(med) = (0.6 x 10^-6m)/1.33= 4.51 x 10^-7 or 451 nm
Now I get looking at this and I'm not sure if that's exactly how I go about doing this or if this is what I'm supposed to do for finding the index of refraction (which comes later) Please help, my brain is fried.