Calculating Temperature Rise of Air in Bicycle Pump

In summary: Um...we haven't even gone over isentropic processes yet but is the equation your're talking about this? PdV + VdP = nRdTUm...we haven't even gone over isentropic processes yet but is the equation your're talking about this? PdV + VdP = nRdT
  • #1
yossup
28
0

Homework Statement



A bicycle pump is a cylinder 20cm long and 3.0cm in diameter. The pump contains air at 21.0C and 1.0atm. If the outlet at the base of the pump is blocked and the handle is pushed in very quickly, compressing the air to half its original volume, how hot does the air in the pump become?

Homework Equations



PV=nRT
PV^gamma = PV^gamma

The Attempt at a Solution



So the intial volume is 1.55m^3. The final volume is .775m^3. And because the handle is pushed very quickly, the process is adiabatic. So I want to know what gamma is but do I use the one for di or triatomic? Then i just use the W = integral P dv?
 
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  • #2
yossup said:

Homework Statement



A bicycle pump is a cylinder 20cm long and 3.0cm in diameter. The pump contains air at 21.0C and 1.0atm. If the outlet at the base of the pump is blocked and the handle is pushed in very quickly, compressing the air to half its original volume, how hot does the air in the pump become?

Homework Equations



PV=nRT
PV^gamma = PV^gamma

The Attempt at a Solution



So the intial volume is 1.55m^3. The final volume is .775m^3. And because the handle is pushed very quickly, the process is adiabatic. So I want to know what gamma is but do I use the one for di or triatomic? Then i just use the W = integral P dv?

Air is composed mostly of Nitrogen and Oxygen (which are diatomic molecules). Thus, the specific heat ratio of air is assigned the value of 1.4.

Since the air is compressed quickly, you may assume it is adiabatic. At relatively low pressures air is also considered to behave as an ideal gas. If you further assume it is a reversible process then you end up with an isentropic process.

Do you know of any relationships that contain the volume, temperature, and specific heat ratio for an isentropic process?

CS
 
  • #3
Um...we haven't even gone over isentropic processes yet but is the equation your're talking about this? PdV + VdP = nRdT
 
  • #4
yossup said:
Um...we haven't even gone over isentropic processes yet but is the equation your're talking about this? PdV + VdP = nRdT

[tex]T_2 = T_1 \cdot \left(\frac{V_1}{V_2}\right)^{k-1} [/tex]

where k is the specific heat ratio.

CS
 

Related to Calculating Temperature Rise of Air in Bicycle Pump

1. What factors affect the temperature rise of air in a bicycle pump?

The temperature rise of air in a bicycle pump is affected by factors such as the volume of air being compressed, the pressure applied, and the speed at which the air is compressed. Other factors that can affect the temperature rise are the ambient temperature and the material and design of the pump itself.

2. How do you calculate the temperature rise of air in a bicycle pump?

The temperature rise of air in a bicycle pump can be calculated by using the ideal gas law, which states that the pressure, volume, and temperature of a gas are directly related. By measuring the initial and final pressure and volume of the air in the pump, the temperature rise can be determined using the equation: T2 = (P2 * V2 * T1) / (P1 * V1), where T1 is the initial temperature and T2 is the final temperature.

3. Why does the temperature rise of air in a bicycle pump matter?

The temperature rise of air in a bicycle pump is important because it can affect the accuracy of tire pressure readings. As the air is compressed, its temperature increases, which can lead to a higher pressure reading than the actual pressure in the tire. This can result in overinflated tires, which can be dangerous and can also cause uneven wear on the tires.

4. Can the temperature rise of air in a bicycle pump be controlled?

The temperature rise of air in a bicycle pump can be controlled to some extent by using a pump with a larger volume and slower compression speed. Additionally, allowing the pump to cool between uses can help reduce the temperature rise. However, some temperature rise is inevitable due to the laws of physics and the heat generated by the compression process.

5. How does the temperature rise of air in a bicycle pump compare to other compression processes?

The temperature rise of air in a bicycle pump is relatively small compared to other compression processes, such as those used in industrial settings. This is because bicycle pumps are designed to compress air at a slower rate and with a larger volume, which helps dissipate the heat. In contrast, industrial compressors often operate at a higher speed and pressure, resulting in a larger temperature rise.

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