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Scarlet_pat
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Homework Statement
A body is undergoing S.H.M. of amplitude 4 x 10-2 m and with a maximum
speedo f 0.20m s-1. Calculate the period of the oscillation given that the velocity,
v, of a body undergoing S.H.M. is ""v= omega sq.rt of A^2 - x ^2"" , where trl is the angular
velocity, A is the maximum displacement and x its displacement from the
equilibrium position
The Attempt at a Solution
T ( period ) = 2 pie / w
since omega is not given, i solved for w with the equation above
v/ sq.root of A^2 - x^ 2 = omega
while v = 0.2 and A = 0.04 m ... what is the value of x ( displacement from the equilibrium position ) ?
i suppose it is the displacement between current position and original position, and if that is true, maximum displacement is = to displacement from equilibrium position ?