Calculating Needed Thrust for a Moon Landing

In summary, to decelerate the landing craft from its initial downwards velocity of 15 m/s to 0 m/s at a vertical distance of 160m above the Moon's surface, a net upward force of 8437.5N is required. This corresponds to an acceleration of -0.703125 m/s^2 due to the Moon's gravity being 1/6th of Earth's.
  • #1
ashvuck101
27
0

Homework Statement



A landing craft of mass 12,000 kg prepares itself for a Moon landing. When at a
vertical distance 160m above the Moon’s surface it’s downwards velocity is 15 m/s.
A retrorocket is fired to give the craft an upward thrust to slow its speed to zero as it
meets the surface. Calculate the needed thrust to decelerate the craft its initial
downwards velocity to zero as it lands. The value for gravity on the Moon is g/6.
(Where g is 9.81m/s2).


Homework Equations



f=ma


The Attempt at a Solution


Gravity =9.81/6
=1.635

F (craft)= ma
=12 000. 1.635
=19620
Therefore the craft will need a a thrust of 19620 N upwards. Is that right or is that other information needed??
 
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  • #2
No that is not right. That upward thrust of 19620N merely counteracts the gravitational force acting on the landing craft. As such, there will be no net force on the craft, and it will continue moving downwards at a constant velocity of 15m/s.

In order to decelerate the craft, you are going to need a net upwards force acting on the craft. Based on the information in the question, what is the magnitude of the upward acceleration that the craft must undergo?
 
  • #3
ok...but i can't calculate an upward force without, Acceleration I am only given constant velocity?? which means there is no acceleration
 
  • #4
There has to be an acceleration for the craft's velocity to reduce to 0 m/s from 15 m/s. I think you should start by calculating the acceleration required to bring the craft's velocity down by 15 m/s in the given distance.
 
  • #5
ok i did that and got -0.703125 as acceleration

then i got a force of -8437.5 N

so the craft needs a downward force of 8437.5N to come to 0 m/s? is it downward or upward??
 

Related to Calculating Needed Thrust for a Moon Landing

1. How do you calculate the needed thrust for a moon landing?

The needed thrust for a moon landing can be calculated by using the rocket equation, which takes into account the mass of the spacecraft, the specific impulse of the engines, and the velocity change required for the landing. This equation is T = (m * Δv) / Isp, where T is the needed thrust, m is the spacecraft mass, Δv is the required velocity change, and Isp is the specific impulse of the engines.

2. What is the specific impulse of an engine?

The specific impulse of an engine is a measure of its efficiency and is defined as the amount of thrust produced per unit of propellant consumed. It is usually measured in seconds and can range from a few hundred seconds for chemical engines to thousands of seconds for electric engines.

3. How does the mass of the spacecraft affect the needed thrust?

The mass of the spacecraft has a direct impact on the needed thrust for a moon landing. The heavier the spacecraft, the more thrust is needed to overcome its weight and achieve the required velocity change. This is why spacecraft designers strive to reduce the mass of the spacecraft as much as possible to minimize the needed thrust and the amount of propellant required.

4. What is the velocity change required for a moon landing?

The velocity change required for a moon landing depends on the specific mission and can vary. However, in general, the spacecraft needs to slow down from a speed of around 1.6 km/s to a complete stop, which requires a velocity change of approximately 1.6 km/s.

5. How do you account for factors like gravity and atmospheric drag when calculating needed thrust for a moon landing?

The rocket equation used to calculate needed thrust for a moon landing already accounts for factors like gravity and atmospheric drag. These factors affect the specific impulse of the engines and the velocity change required for the landing, which are both included in the equation. However, other factors like navigation errors and engine performance variations may also need to be considered and accounted for in the calculations.

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