- #1
sabak22
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Homework Statement
A capacitor is completely charged with 670 nC by a voltage source that had 200 V.
What is its capacitance?==== 3.35×10-9 F 9(I got this y doing Q/V)
The initial air gap of the capacitor above was 7 mm. What is the stored energy if the air gap is now 10 mm?
Now this is the part with which I am stuck
The Attempt at a Solution
I know that Energy = (1/2)CV^2 or QV/2, as well as Q^2/2C
But the problem is, I don't know what steps should be done before i reach the last step for calculating the energy stored. Please help!