No. You are asked for an x-component, which can be negative or positive. Make a sketch to find the right sign. What does the F in your relevant equation represent ?Jrlinton said:
.The electrostatic force between two charged particles is calculated using Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula for calculating the electrostatic force is F = (k * q1 * q2) / d2, where k is the Coulomb's constant, q1 and q2 are the charges of the particles, and d is the distance between them.
The unit of electrostatic force is Newton (N), which is equivalent to kg*m/s2. It is a unit of force that represents the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared.
The electrostatic force between two charged particles is inversely proportional to the square of the distance between them. This means that as the distance between the particles increases, the force decreases. Similarly, as the distance decreases, the force increases. This relationship can be seen in the formula F = (k * q1 * q2) / d2.
Yes, the electrostatic force can be both attractive and repulsive. If the charges of the particles are of opposite sign, the force between them will be attractive, pulling the particles towards each other. On the other hand, if the charges are of the same sign, the force will be repulsive, pushing the particles away from each other.
The magnitude of the charges has a direct effect on the electrostatic force between particles. The greater the magnitude of the charges, the stronger the force will be. For example, if the charges are doubled, the force between the particles will also double. This relationship can be seen in the formula F = (k * q1 * q2) / d2.