Calculating Electric Force & Charge for Physics Problems

F3 = 1.75e9Then I took the x components of these forces as: F1x = 1.65e9 cos(45) F2x = 1.53e9 cos(45) ...and... F3x = 1.75e9 cos(45)And I took the y components as: F1y = 1.65e9 sin(45) F2y = 1.53e9 sin(45) ...and... F3y = 1.75e9 sin(45)Then I added the x components together and the y components together, to get a net force of:
  • #1
Kawrae
46
0
1. Four identical point charges (q = +30.0 µC) are located on the corners of a rectangle. The dimensions of the rectangle are L = 70.0 cm and W = 20.0 cm. Calculate the magnitude and direction of the net electric force exerted on the charge at the lower left corner by the other three charges.

>> I'm not sure what I did wrong with this one. Basically, what I did was use F=ke[(|q1| |q2|)/r^2] for the three sides effecting the lower left corner one. Then I took these forces and broke them into x and y components, added them together, and then used the pythagorean theorem to find F. I got an answer of 2.15e10. Then for the direction, I said it would be 45 degrees counter clockwise from the x-axis, because since they are all positive charges, they would repel each other.

Any idea what I'm doing wrong?

2. Two small silver spheres, each with a mass of 9.00 g, are separated by 1.00 m. Calculate the fraction of the electrons in one sphere that must be transferred to the other to produce an attractive force of 2.00e4(about 2 tons) between the spheres. (The number of electrons per atom of silver is 47, and the number of atoms per gram is Avogadro's number divided by the molar mass of silver, 107.87 g/mol.)

>> I have absolutely no idea how to start this one. The only thing I can think of would be F=ke[(|q1||q2|)/r^2], but I don't think that's right... argh!

3. This one goes with a picture -> q1 and q2 are on the x-axis separated by 1.00 m. (q1 = -2.7 µC, q2 = 6.00 µC), determine the point (other than infinity) at which the electric field is zero.

>> All I know with this is that the point is going to have to be to the left of q1. But I don't know how to find the exact point!

Any help would be greatly appreciated! I'm going insane :bugeye:
 
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  • #2
Kawrae said:
1. Four identical point charges (q = +30.0 µC) are located on the corners of a rectangle. The dimensions of the rectangle are L = 70.0 cm and W = 20.0 cm. Calculate the magnitude and direction of the net electric force exerted on the charge at the lower left corner by the other three charges.

>> I'm not sure what I did wrong with this one. Basically, what I did was use F=ke[(|q1| |q2|)/r^2] for the three sides effecting the lower left corner one. Then I took these forces and broke them into x and y components, added them together, and then used the pythagorean theorem to find F. I got an answer of 2.15e10. Then for the direction, I said it would be 45 degrees counter clockwise from the x-axis, because since they are all positive charges, they would repel each other.

Any idea what I'm doing wrong?
This would be true for a square, but not for a rectangle. The disances from 1 charge to the others are not equal, hence the forces are not equal. What are the distances of the other 3 charges? It's hard to say exactly what went wrong without seeing all your work.

2. Two small silver spheres, each with a mass of 9.00 g, are separated by 1.00 m. Calculate the fraction of the electrons in one sphere that must be transferred to the other to produce an attractive force of 2.00e4(about 2 tons) between the spheres. (The number of electrons per atom of silver is 47, and the number of atoms per gram is Avogadro's number divided by the molar mass of silver, 107.87 g/mol.)

>> I have absolutely no idea how to start this one. The only thing I can think of would be F=ke[(|q1||q2|)/r^2], but I don't think that's right... argh!
When you transfer electrons from one neutral object to another, then each obtains equal charges of opposite sign. You can use coulomb's equation to find the charge noting that q1 = q2. Once you know the charge, you can solve the rest by finding out how many elcetrons are in a gram of silver etc etc...

3. This one goes with a picture -> q1 and q2 are on the x-axis separated by 1.00 m. (q1 = -2.7 µC, q2 = 6.00 µC), determine the point (other than infinity) at which the electric field is zero.

>> All I know with this is that the point is going to have to be to the left of q1. But I don't know how to find the exact point!

Any help would be greatly appreciated! I'm going insane :bugeye:
I assume q1 is to the left of q2. Treat the distance of this point from q1 as a variable (say x), then what is the distance from q2? What can be said about the individual electric field contributions from q1 and q2 at this point? What is the equation for electric field?
 
Last edited:
  • #3
MathStudent said:
This would be true for a square, but not for a rectangle. The disances from 1 charge to the others are not equal, hence the forces are not equal. What are the distances of the other 3 charges? It's hard to say exactly what went wrong without seeing all your work.

Um okay, the distance from the bottom left corner to the top left corner is 20.0 cm, the distance from the bottom left corner to the top right corner is 72.8cm and the distance from the bottom left corner to the bottom right corner is 70.0cm.

I'll try and post my work here, but I don't know how to use latex (sorry):
I used F=ke[(|q1| |q2|)/r^2] for all three corners and how they effect the bottom left. I got those forces as:
F1 = 1.65e9
F2 = 1.53e9
F3 = 2.02e10

Then I broke them up into components and added them together, so the resulting Forces x and y components would be 2.73e9 (x) and 2.13e10 (y) and I used pathagoreans theorem to get a final answer of 2.15e10 :frown:


MathStudent said:
When you transfer electrons from one neutral object to another, then each obtains equal charges of opposite sign. You can use coulomb's equation to find the charge noting that q1 = q2. Once you know the charge, you can solve the rest by finding out how many elcetrons are in a gram of silver etc etc...

I used Coulomb's and found the charge should be 2.22e-6... and there are 2.36e24 I'm not sure what to do with this information though now to solve the question? :confused:



MathStudent said:
I assume q1 is to the left of q2. Treat the distance of this point from q1 as a variable (say x), then what is the distance from q2? What can be said about the individual electric field contributions from q1 and q2 at this point? What is the equation for electric field?

Oy I'm still very confused. The equation is E=Fe/q0 ... I am not sure about the individual field contributions from q1 and q2, only that they will both be 0 and this point. Rawr I am still so lost... :cry:
 
  • #4
For the first part, be careful with units!

Distance is always calculated in terms of meters not centimeters.
[itex]\mu C[/itex] stands for 10^-6 C

All the magnitudes of your forces are off by a factor of 10^8 (probably for the reasons mentioned above)

The components you calculated for the net force are incorrect.
F1 points in the x direction
F2 points in the y direction
F3 lies along the diagonal of the rectangle, so it needs to be broken into its x and y components
(you decide + & - directions and set up coordinates)
remember all forces are repulsive

if theta is the angle between F3 and the x axis, then

[tex]F3_x = F3cos \theta [/tex]

[tex]F3_y = F3sin \theta [/tex]

once you have the net force in terms of x and y components, then the magnitude of force is calculated by

[tex] | \vec{F_{net}}| = \sqrt{F_x^2 + F_y^2} [/tex]

The angle (phi) that [itex] \vec{F_{net}} [/itex] makes with the x-axis is

[tex] \phi = tan^{-1}( \frac{F_x}{F_y})[/tex]

Remeber to check signs, which is up to your defined coordinates.
 

Related to Calculating Electric Force & Charge for Physics Problems

1. How do I calculate the electric force between two point charges?

The electric force between two point charges can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them. The equation is F = k(q1q2)/r2, where k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

2. What is the unit of electric force?

The unit of electric force is Newton (N). It is derived from the basic SI units of charge (C) and distance (m), and is equivalent to kg*m/s2.

3. How do I calculate the electric force between multiple point charges?

To calculate the electric force between multiple point charges, you can use the superposition principle, which states that the total force on a charge is the vector sum of the individual forces from each charge. This means that you can calculate the force between each pair of charges using Coulomb's Law and then add them together to find the total force.

4. Can the electric force between two charges be negative?

Yes, the electric force between two charges can be negative. This occurs when the charges have opposite signs (one positive and one negative), which results in an attractive force. When the charges have the same sign, the force is repulsive and will be positive.

5. How does the distance between two charges affect the electric force?

The distance between two charges has an inverse square relationship with the electric force. This means that as the distance between the charges decreases, the force increases exponentially. Conversely, as the distance increases, the force decreases exponentially. This relationship is described by the inverse square law in Coulomb's Law.

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