Calculating Building Height: Quick Kinematics Question

  • Thread starter Cookies?
  • Start date
  • Tags
    Kinematics
In summary, the conversation involves trying to calculate the total height of a building by using the given information that a stone dropped from the top of the building travels 1/5 of the building's height in the last second before hitting the ground. The person is struggling to use simultaneous equations and is seeking help on finding the speed of the stone just before it hits the ground. They also discuss options for solving the problem and mention that more information is not necessary as the unknowns will cancel out.
  • #1
Cookies?
4
0
A stone is dropped from the top of a building. Within the second before it hits the ground, it travels 1/5 of the building's height. Calculate the total height of the building.

Been trying to formulate simultaneous equations but there just doesn't seem to be enough information and too many unknowns >< Help appreciated!
 
Physics news on Phys.org
  • #2
What is the speed of the stone just before it hits the ground? You only need one equation.
 
  • #3
Show what you've done so far. How would you write the distance fallen as a function of time?
 
  • #4
You don't need more info either as the unknowns will eventually cancel out. There are actually a couple of different ways to solve this.
 
Last edited:
  • #5


Hello,

Thank you for your question. I can provide a solution to your problem.

To calculate the height of the building, we can use the equation for the distance traveled by an object in free fall:

d = 1/2 * g * t^2

Where d is the distance traveled, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

We know that in the last second before the stone hits the ground, it travels 1/5 of the building's height. Therefore, we can write the following equation:

1/5 * h = 1/2 * g * 1^2

Where h is the height of the building.

Simplifying this equation, we get:

h = 5/2 * g

Now, we also know that the total distance traveled by the stone is equal to the height of the building. Therefore, we can write the following equation:

h = 1/2 * g * t^2

Substituting the value of h from the previous equation, we get:

5/2 * g = 1/2 * g * t^2

Simplifying this equation, we get:

t^2 = 5

Taking the square root of both sides, we get:

t = √5 ≈ 2.236

This means that the total time taken by the stone to hit the ground is approximately 2.236 seconds.

Now, we can use this value of t in the equation for the height of the building to calculate the total height:

h = 1/2 * g * t^2

Substituting the value of t, we get:

h = 1/2 * 9.8 * (2.236)^2

Simplifying this equation, we get:

h ≈ 24.5 meters

Therefore, the total height of the building is approximately 24.5 meters.

I hope this helps. Let me know if you have any further questions or need clarification.

Best regards,

 

Related to Calculating Building Height: Quick Kinematics Question

What is quick kinematics?

Quick kinematics is a branch of physics that studies the motion of objects without taking into account the causes of motion, such as forces or energy.

What are the three types of quick kinematics?

The three types of quick kinematics are translational, rotational, and oscillatory. Translational kinematics deals with the motion of objects in a straight line, rotational kinematics deals with the motion of objects around a fixed axis, and oscillatory kinematics deals with the motion of objects back and forth around an equilibrium position.

What are the basic equations used in quick kinematics?

The basic equations used in quick kinematics are displacement (Δx = xf - xi), velocity (v = Δx/Δt), and acceleration (a = Δv/Δt).

What is the difference between quick kinematics and general kinematics?

The main difference between quick kinematics and general kinematics is that quick kinematics does not take into account external forces or energy, while general kinematics does. Quick kinematics is a simplified version of general kinematics and is often used for quick calculations or approximations.

How is quick kinematics used in real life?

Quick kinematics is used in many real-life applications, such as analyzing the motion of vehicles, projectiles, and sports movements. It is also used in engineering to design and optimize machines and structures, as well as in video game development for realistic animations. Additionally, quick kinematics is used in robotics and automation to control the motion of machines and robots.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
2
Replies
35
Views
4K
  • Introductory Physics Homework Help
2
Replies
38
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
3K
  • Introductory Physics Homework Help
Replies
14
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
2K
Back
Top