Calculating Angular Acceleration of a Washer's Tub

In summary, the tub of a washer goes through a total of 2.2 revolutions during its spin-dry cycle, starting from rest and reaching a final angular speed of 2.2 revolutions/s in 8.4 seconds. The person opening the lid causes the washer to slow down and come to a stop in 9.5 seconds. This means the tub goes through 2.2 revolutions from rest to final velocity, and another 2.2 revolutions from final velocity to rest, for a total of 4.4 revolutions.
  • #1
smd1991
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1. The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.2 revolutions/s in 8.4 seconds. at this point the person doing the laundry opens the lid, and a safety switch turns off the washer, the tub slows to rest in 9.5 seconds.
through how many revolutions does the tub turn? assume constant angular acceleration while it is starting and stopping. answer in units of revolution.




i don't even know where to start really, besides finding the angular acceleration
 
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  • #2
Do you have the kinematics equations for angular displacement? The process is exactly the same as how you would do it linearly.

1. washing machine starts from rest and goes to a final velocity of 2.2 in 8.4s.
2. washing machine then goes from 2.2 to rest in 9.5s.
3. what is the total distance traveled by washing machine (freaky huh, washing machines that can run out of the house).
 
  • #3
. we can use the formula ωf = ωi + αt to find the angular acceleration. ωf is the final angular speed (2.2 revolutions/s), ωi is the initial angular speed (0 revolutions/s), α is the angular acceleration, and t is the time (8.4 seconds). rearranging the formula, we get α = (ωf - ωi)/t. plugging in the values, we get α = (2.2 - 0)/8.4 = 0.262 revolutions/s^2.

now, using the formula θ = ωi*t + 0.5*α*t^2, we can find the number of revolutions the tub turns while accelerating. θ is the total angle turned (unknown), ωi is the initial angular speed (0 revolutions/s), t is the time (8.4 seconds), and α is the angular acceleration (0.262 revolutions/s^2). rearranging the formula, we get θ = 0.5*α*t^2. plugging in the values, we get θ = 0.5*0.262*8.4^2 = 9.856 revolutions.

since the tub reaches an angular speed of 2.2 revolutions/s, it will turn an additional 2.2 revolutions in the 9.5 seconds it takes to slow down and come to rest. therefore, the total number of revolutions the tub turns is 9.856 + 2.2 = 12.056 revolutions.

assuming constant angular acceleration while starting and stopping, the tub turns 12.056 revolutions in total.
 

1. What is angular acceleration?

Angular acceleration is the rate at which the angular velocity of an object changes over time. It is measured in radians per second squared (rad/s^2) in the SI system.

2. How do you calculate angular acceleration?

Angular acceleration can be calculated by dividing the change in angular velocity by the change in time. The formula for angular acceleration is α = (ω2 - ω1) / (t2 - t1), where α is the angular acceleration, ω is the angular velocity, and t is the time.

3. What is the difference between linear acceleration and angular acceleration?

Linear acceleration refers to the rate of change of an object's linear velocity, while angular acceleration refers to the rate of change of an object's angular velocity. Linear acceleration is measured in meters per second squared (m/s^2) while angular acceleration is measured in radians per second squared (rad/s^2).

4. How does the mass of the washer's tub affect the angular acceleration?

The mass of the washer's tub does not directly affect the angular acceleration. However, it can indirectly affect the angular acceleration by affecting the torque applied to the tub and therefore the angular velocity. A heavier tub would require more torque to rotate at the same angular velocity, resulting in a lower angular acceleration.

5. Can angular acceleration be negative?

Yes, angular acceleration can be negative. A negative angular acceleration indicates that the angular velocity is decreasing over time, resulting in a deceleration or slowing down of the rotational motion. This can occur when there is an external torque acting in the opposite direction of the rotational motion.

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