- #1
Emilyyyyyyyyy
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- Homework Statement
- I have this scenerio where a man A jumps from a 400 m building. He is caught 5 meters below by man B (so at 395 m). man A hits with man B given his mass is 79.4 kg and the horizontal distance travelled is 3.86 meters, all in 1.5 seconds. How do I calculate the force that man A hits man B with?
- Relevant Equations
- vx = dx/t
W = FnetΔd
To find vx
vx = dx/t = 3.86 m/1.5 s= 2.573 m/s
To find Ek
Ek = ½mvx²= ½(79.4)(2.573)²= 262.8 J
W = FnetΔd
Fnet = 262.8 J/ 3.86 m = 68 N
He hits him with a force of 68N
vx = dx/t = 3.86 m/1.5 s= 2.573 m/s
To find Ek
Ek = ½mvx²= ½(79.4)(2.573)²= 262.8 J
W = FnetΔd
Fnet = 262.8 J/ 3.86 m = 68 N
He hits him with a force of 68N