pippintook said:A 10-m long cable has a "No Hippos in the Pool" sign weighing 25-N suspended from the middle of the cable. The cable stretches by 2.5 cm. What is the strain in the cable?
I know strain is ΔL/L0, but don't really know how that plays out in this scenario. If you could give me the first step or so, that'd be great!
pippintook said:Well, my problem is more how I find L than how to find strain I guess.
To calculate the strain of a cable, you will need to know the length of the cable (in meters) and the applied force (in Newtons). Then, you can use the formula strain = force / length to find the strain of the cable.
The equation for calculating strain is strain = force / length. This equation takes into account both the length of the cable and the amount of force applied to it.
Sure, let's say we have a cable that is 10 meters long and has a force of 25 Newtons applied to it. Using the equation strain = force / length, we can calculate the strain as follows: strain = 25 N / 10 m = 2.5 N/m. Therefore, the strain of the cable is 2.5 N/m.
Strain and stress are related but different concepts. Strain is a measure of the deformation or elongation of a material, while stress is a measure of the internal forces acting within a material. In the context of a cable, strain is a measure of how much the cable has stretched under the applied force, while stress is a measure of the internal forces within the cable that are resisting the applied force.
Some common units for strain include meters per meter (m/m), millimeters per meter (mm/m), and inches per inch (in/in). These units represent the amount of deformation per unit length of the material.