- #1
meemosewa
- 9
- 0
Using Kepler's Third Law, give the formula for the period TX of planet X whose orbital radius RX is twice that of earth, RE.
A. TX=(1 Year)x(RX/RE)^3
B. TX^2=(1 Year)x(RX/RE)^3
C. TX=(1 Year)x(RE/RX)^3
D. TX^2=(1 Year)x(RE/RX)^3
My book is not giving me a formula to use, so i a totally stuck... and ideas?
A. TX=(1 Year)x(RX/RE)^3
B. TX^2=(1 Year)x(RX/RE)^3
C. TX=(1 Year)x(RE/RX)^3
D. TX^2=(1 Year)x(RE/RX)^3
My book is not giving me a formula to use, so i a totally stuck... and ideas?