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Homework Statement
A certain substance has a mass per mole of 55 g/mol. When 284 J is added as heat to a 32.0 g sample of this material, its temperature rises from 22.0°C to 39.5°C
And I know that the specific heat of this substance is 507.14 J/[kg(K)]
Homework Equations
Q = mc[tex]\Delta[/tex]T
The Attempt at a Solution
55 g/mol * (1/32g) = 1.71875mol
284J/[(1.71875mol)/(39.5-22)] = 9.44 J/[mol(K)]
however..this is wrong and now I'm not sure where to go..help pleeeease!