Area of Triangle ABC: Find the Answer Here

In summary, by extending AC to E such that ACD is similar to ECB, we can find the area of triangle ABC by using the similarity ratio of 3:1. Therefore, the area of triangle ABC is 18.
  • #1
ketanco
15
0
what is the area of triangle ABC in the attached? answer is 18

i can not construct any similar triangles here. all i can see is area of ACD is 3 times area of ABD but how does it help me...
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  • #2
ketanco said:
what is the area of triangle ABC in the attached? answer is 18

i can not construct any similar triangles here. all i can see is area of ACD is 3 times area of ABD but how does it help me...

How about extending AC to E such that ACD is similar to ECB?

[TIKZ]
\def\x{sqrt(265)/4}
\def\gamma{atan2(3,16)}
\coordinate[label=above:A] (A) at ({4*\x - 12 * cos(\gamma)},{12 * sin(\gamma)});
\coordinate[label=left:B] (B) at (0,0);
\coordinate[label=right:C] (C) at ({4*\x},0);
\coordinate[label=below:D] (D) at ({\x},0);
\coordinate[label=above:E] (E) at ({4*\x - 16 * cos(\gamma)},{16 * sin(\gamma)});

\draw[rotate={270-\gamma}] (A) +(0.4,0) -- +(0.4,0.4) -- +(0,0.4);
\draw[rotate={270-\gamma}] (E) +(0.4,0) -- +(0.4,0.4) -- +(0,0.4);

\draw (C) -- node[above] {12} (A) -- node[above left] {5} (B);
\draw (A) -- (D);
\draw (A) -- (E) -- (B);
\path (B) -- node[below] {$x$} (D) -- node[below] {$3x$} (C);
\draw[blue, ultra thick] (A) -- (B) -- (C) -- cycle;
[/TIKZ]
 
  • #3
Klaas van Aarsen said:
How about extending AC to E such that ACD is similar to ECB?

[TIKZ]
\def\x{sqrt(265)/4}
\def\gamma{atan2(3,16)}
\coordinate[label=above:A] (A) at ({4*\x - 12 * cos(\gamma)},{12 * sin(\gamma)});
\coordinate[label=left:B] (B) at (0,0);
\coordinate[label=right:C] (C) at ({4*\x},0);
\coordinate[label=below:D] (D) at ({\x},0);
\coordinate[label=above:E] (E) at ({4*\x - 16 * cos(\gamma)},{16 * sin(\gamma)});

\draw[rotate={270-\gamma}] (A) +(0.4,0) -- +(0.4,0.4) -- +(0,0.4);
\draw[rotate={270-\gamma}] (E) +(0.4,0) -- +(0.4,0.4) -- +(0,0.4);

\draw (C) -- node[above] {12} (A) -- node[above left] {5} (B);
\draw (A) -- (D);
\draw (A) -- (E) -- (B);
\path (B) -- node[below] {$x$} (D) -- node[below] {$3x$} (C);
\draw[blue, ultra thick] (A) -- (B) -- (C) -- cycle;
[/TIKZ]
i see... thanks !
 

1. What is the formula for finding the area of a triangle?

The formula for finding the area of a triangle is A = 1/2 * base * height, where A represents the area, the base is the length of the triangle's base, and the height is the perpendicular distance from the base to the opposite vertex.

2. How do you find the base and height of a triangle?

The base and height of a triangle can be found by measuring the length of the base and the perpendicular distance from the base to the opposite vertex. Alternatively, if the coordinates of the vertices of the triangle are known, the base and height can be calculated using the distance formula.

3. Can the area of a triangle be negative?

No, the area of a triangle cannot be negative. It is always a positive value as it represents the amount of space enclosed by the triangle.

4. Is the area of a triangle the same for all types of triangles?

No, the area of a triangle is not the same for all types of triangles. It depends on the length of the base and the height, which can vary for different types of triangles.

5. How do you use the area of a triangle in real life?

The area of a triangle is used in many real-life applications, such as in construction, architecture, and engineering. It is also used in calculating the surface area of 3D objects, and in measuring distances and angles in navigation and surveying.

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