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I have posted a link there to this topic so the OP can see my work.Differentiate each function and find the equation of the tangent line at x=a?

1. y=(x+(1/x))^2 ; a=0.5

I took the derivative and got 2(x+(1/x))(1-(1/(x^2))

I plugged a=0.5 for x and got y=6.25

What is y' and how do I plug this into slope-intercept form to find the equation?

2. y=e^x+e^-x ; a=0

I took the derivative and got e^x-e^-x.

I plugged 0 in for x and got y=2

What is y' and how do I plug this into slope-intercept form to find the equation?