Angle at Y-axis Crossing of y=sin(1/x) Graph

MHB
Thread starter wheepep
Start date Dec 4, 2020
Tags

Angle Graph

In summary, the graph of y=sin(1/x) has a series of peaks and valleys that approach the x-axis but never touch it. It oscillates infinitely as x approaches 0 and does not cross the y-axis at any point. It also crosses the x-axis an infinite number of times and is symmetrical about the origin, but not the y-axis. The limit of y=sin(1/x) as x approaches 0 is undefined.

Dec 4, 2020

wheepep

at which angle does the graph y=sin(1/x) cross the y-axis??

Mathematics news on Phys.org

Dec 5, 2020

Theia

Value undefined: the function is discontinuous at x = 0, which means, the graph doesn't cross the y-axis.

1. What is the shape of the graph of y=sin(1/x)?

The graph of y=sin(1/x) is a continuous, oscillating curve that approaches the x-axis as x approaches infinity and negative infinity.

2. What is the angle at the y-axis crossing of the graph of y=sin(1/x)?

The angle at the y-axis crossing of the graph of y=sin(1/x) is undefined, as the graph approaches the y-axis at an infinite number of points.

3. How does the angle at the y-axis crossing change as x approaches zero?

As x approaches zero, the angle at the y-axis crossing of the graph of y=sin(1/x) becomes steeper and approaches a vertical angle.

4. What is the period of the graph of y=sin(1/x)?

The period of the graph of y=sin(1/x) is not defined, as the graph does not have a repeating pattern.

5. How does the angle at the y-axis crossing change as the frequency of the graph increases?

As the frequency of the graph increases, the angle at the y-axis crossing becomes steeper and approaches a vertical angle. This is because the graph oscillates more frequently and approaches the y-axis at a greater number of points.