- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,198

- Thread starter Ackbach
- Start date

- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,198

- Admin
- #2

- Mar 5, 2012

- 9,416

When you do a long division with regular numbers, you are converting the result to decimal form: $\sum a_i 10^i$.

By convention all $a_i$ are between 0 and 9.

We don't

We can also use a different base than 10, say 16.

Or we can choose that all $a_i$ should be between -5 and +4.

That way you'll get a different representation of the result, similar to doing polynomial division.

Note that if you define x=10 in polynomial division, and also constrain the factors to be between 0 and 9, you get regular long division.

- Feb 9, 2012

- 33

$ \ \ \ $ 6000 - 900 + 100 + 20 + 5 - 1

_________ ________ ________ ________ ________ _____

58 | 302985

-(348000)

________________ ___________ ________ ___

-45015

-(-52200)

______________ ______________ ______

7185

-(5800)

____ __________ ____________ ____

1385

-(1160)

_______ ____________ ___________ ______

225

-(290)

____ _______ _____________ ______ _____

-(65)

-(-58)

_________ _______________ ________

-7

You can stop now if you're bored or you can continue for as long as you like , what i have done is make a guess at each step until the subtraction produced a number that is obviously a remainder , -7. It doesn't matter if i go 'over' or 'under' at any step AND it doesn't matter by how much i am in error , the rules of arithmetic (and algebra indirectly) gaurantee the result is true.

$ 6000 - 900 + 100 + 20 + 5 - 1 - \frac{7}{58} = 5224 - \frac{7}{58} = 302985 ÷ 58 $

- Feb 9, 2012

- 33

$ \ \ \ $ 2 - 1

$ \ \ \ $ _______

7 | 9

-(14)

__________

-5

-(-7)

______

2

So the answer is $ \ \ 2 - 1 + \frac{2}{7} = 1 + \frac{2}{7} $

Note that we can stop after the first 'guess' of 2 and we would get

$ 2 - \frac{5}{7} $

which is the correct answer. So at every step the algorithm produces a correct answer ... in my previous post as well ... it must be , otherwise we would not get the correct answer in the end because each subsequent calculation depends on the previous calculation , but some answers are more useful than others , depending on what you like or are looking for a particular representation of the same correct answer.

- Thread starter
- Admin
- #5

- Jan 26, 2012

- 4,198

When you do a long division with regular numbers, you are converting the result to decimal form: $\sum a_i 10^i$.

By convention all $a_i$ are between 0 and 9.

We don'thaveto do it that way though.

We can also use a different base than 10, say 16.

Or we can choose that all $a_i$ should be between -5 and +4.

That way you'll get a different representation of the result, similar to doing polynomial division.

Note that if you define x=10 in polynomial division, and also constrain the factors to be between 0 and 9, you get regular long division.

$ \ \ \ $ 6000 - 900 + 100 + 20 + 5 - 1

_________ ________ ________ ________ ________ _____

58 | 302985

-(348000)

________________ ___________ ________ ___

-45015

-(-52200)

______________ ______________ ______

7185

-(5800)

____ __________ ____________ ____

1385

-(1160)

_______ ____________ ___________ ______

225

-(290)

____ _______ _____________ ______ _____

-(65)

-(-58)

_________ _______________ ________

-7

You can stop now if you're bored or you can continue for as long as you like , what i have done is make a guess at each step until the subtraction produced a number that is obviously a remainder , -7. It doesn't matter if i go 'over' or 'under' at any step AND it doesn't matter by how much i am in error , the rules of arithmetic (and algebra indirectly) gaurantee the result is true.

$ 6000 - 900 + 100 + 20 + 5 - 1 - \frac{7}{58} = 5224 - \frac{7}{58} = 302985 ÷ 58 $

Excellent! So the analogy was always there under my very nose; but because regular long division is hardly ever taught this way (ever taught this way?), it would not be obvious unless you go looking for it. This relieves the tension in my mind between the two; it seemed to me that the analogy had to be exact! You really are doing the same math.

$ \ \ \ $ 2 - 1

$ \ \ \ $ _______

7 | 9

-(14)

__________

-5

-(-7)

______

2

So the answer is $ \ \ 2 - 1 + \frac{2}{7} = 1 + \frac{2}{7} $

Note that we can stop after the first 'guess' of 2 and we would get

$ 2 - \frac{5}{7} $

which is the correct answer. So at every step the algorithm produces a correct answer ... in my previous post as well ... it must be , otherwise we would not get the correct answer in the end because each subsequent calculation depends on the previous calculation , but some answers are more useful than others , depending on what you like or are looking for a particular representation of the same correct answer.

- Feb 9, 2012

- 33

1156432 ÷ 7

I'm going to follow the rules by putting 7 into 11 once then 7 into 45 6 times then 7 into 36 5 times , then break the rules and start 'guessing'

So far i've got this ,

$ \ \ \ \ \ \ $ 165' + 200 + 5

$ \ \ \ $ __________ ________

7 | 1156432

$ \ $ -(1155000)

$ \ \ $ ________ ________ ___

$ \ \ \ \ \ \ \ \ \ \ $ 1432

$ \ \ \ \ \ \ \ \ $ -(1400)

$ \ \ $ ________ ________ ________

$ \ \ \ \ \ \ \ \ \ \ \ \ \ \ $ 32

$ \ \ \ \ \ \ \ \ \ \ \ $ -(35)

$ \ \ $ ________ ________ ________

$ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ $ -3

That 165 represents 165000 because i'm 'honoring' place value , now start the guesswork and break the rule , any way you like ... i make a 'guess' that 7 will go into 1432 200 times then subtract 1400 and then 'guess' 7 will go into 32 5 times so that i can break the other rule about 'positive remainders'

Puting it all together gives $ 165000 + 200 + 5 - \frac{3}{7} = 165205 - \frac{3}{7}$

I could have made different 'guesses' , more wildly inaccurate 'guesses' , the procedure would have been longer but if do my arithmetic correctly , every step is a valid representation of the answer.

We could put a mark on 165 to let us know we're breaking the rule after that point and make a note

165' = 165000

as i have done above.