- #1
td21
Gold Member
- 177
- 8
Why is $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n-1}
$$? This is in a textbook and says that its proof is left as an exercise. It seems to be a difficult equality.
I believe this should just be $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n}
$$ by simple differentiation.
Am I wrong or not?
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n-1}
$$? This is in a textbook and says that its proof is left as an exercise. It seems to be a difficult equality.
I believe this should just be $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n}
$$ by simple differentiation.
Am I wrong or not?