- #1
leonida
- 10
- 0
Homework Statement
prove that with flow in a corner, with stream function ψ=Axy, particles are accelerating per [itex]\frac{DV}{Dt}[/itex]=(A2(x2-y2))/r; A=const; r-distance from the center of the corner
Homework Equations
Vx=U=[itex]\frac{∂ψ}{∂y}[/itex] . . Vy=V=-[itex]\frac{∂ψ}{∂x}[/itex]
a=[itex]\frac{∂V}{∂t}[/itex]+U[itex]\frac{∂V}{∂x}[/itex]+[itex]\frac{∂V}{∂y}[/itex]
The Attempt at a Solution
As per above equations i get velocity components as
U=Ax and V=-Ay
then since local acc is 0 acceleration is:
a=Ax[itex]\frac{A(x-y)}{∂x}[/itex] - Ay[itex]\frac{A(x-y)}{∂y}[/itex]
finally, as per my calcs, accelerations is:
a=A2(x+y)
where did this r come from and also (x2-y2). i was thinking using r2=x2+y2, and using to multiply the whole acceleration expression with r2/(x2+y2), but i am getting nowhere.
help please