Activity of I_131 after 2 days

  • Thread starter soopo
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In summary, the initial activity of I_131 is 0.74MBq and its half time is 8 days. After two days, the activity is expected to be 250 kBq. However, this answer is 0.4 times less than the expected value, which may be due to the fact that only 40% of the activity in a human is of the form I_131.
  • #1
soopo
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Homework Statement


The initial activity of I_131 is 0.74MBq.
The half time of I_131 is 8 days.

How large is the activity after two days?

Homework Equations



[tex] A = A_0 e^{-\lambda t} [/tex]

The Attempt at a Solution



We know
t = 2 days
A_0 = 0.74 MBq
T_0.5 = 8 days

1. Solve the activity constant
[tex] \lambda = ln2 / T_0.5 [/tex]

2. Plug it to the equation
[tex] A = A_0 e^{(-ln2 / T_0.5) * t} [/tex]

I standardise the units to SI and then omit/cancel them
[tex] A = 0.74E6 * e^{-ln2 / 4} [/tex]
[tex] = 6.22E5 Bq [/tex]

---

The right answer is 0.4 times what I get
[tex] A = 0.4 * 6.22E5 Bq [/tex]
[tex] = 250 kBq[/tex]

I am not sure where the 0.4 is got.
 
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  • #2
soopo said:

Homework Statement


The initial activity of I_131 is 0.74MBq.
The half time of I_131 is 8 days.

How large is the activity after two days?


Homework Equations



[tex] A = A_0 e^{-\lambda t} [/tex]


The Attempt at a Solution



We know
t = 2 days
A_0 = 0.74 MBq
T_0.5 = 8 days

1. Solve the activity constant
[tex] \lambda = ln2 / T_0.5 [/tex]

2. Plug it to the equation
[tex] A = A_0 e^{(-ln2 / T_0.5) * t} [/tex]

I standardise the units to SI and then omit/cancel them
[tex] A = 0.74E6 * e^{-ln2 / 4} [/tex]
[tex] = 6.22E5 Bq [/tex]

---

The right answer is 0.4 times what I get
[tex] A = 0.4 * 6.22E5 Bq [/tex]
[tex] = 250 kBq[/tex]

I am not sure where the 0.4 is got.

The problem is now solved.

There is the following sentence two pages before the exercise
"Only 40% of the activity in a human is of the form I_131"
 
  • #3
The 0.4 is likely the result of rounding or approximation. When using the half-life formula, the actual value after 2 days would be 249.4 kBq, which is approximately 250 kBq. This slight difference may also be due to rounding of the half-life value or the initial activity value. It is important to note that these calculations are based on ideal conditions and may not reflect the exact activity in a real-life scenario. Other factors, such as decay processes and environmental factors, may also affect the activity of I_131. It is always important to consider these factors when interpreting scientific data.
 

Related to Activity of I_131 after 2 days

1. What is I-131 and why is its activity important?

I-131 is a radioactive isotope of iodine. Its activity is important because it is commonly used in medical procedures, such as thyroid scans and treatments for thyroid cancer.

2. How long does it take for the activity of I-131 to decrease?

The half-life of I-131 is 8.02 days, which means that after 8.02 days, the activity will decrease by half. After 16.04 days, it will decrease by half again, and so on.

3. Is the activity of I-131 dangerous after 2 days?

It depends on the dosage and exposure. In most cases, the activity of I-131 after 2 days is not considered dangerous. However, it is important to follow safety protocols and handle it carefully.

4. Can the activity of I-131 be detected after 2 days?

Yes, the activity of I-131 can still be detected after 2 days, but it will be significantly lower than its initial activity. The amount of activity that can be detected also depends on the sensitivity of the detection equipment.

5. What are the potential risks associated with the activity of I-131?

The main risk associated with the activity of I-131 is exposure to radiation, which can be harmful to living organisms. It is important to handle it with caution and follow proper safety measures to minimize the risks.

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