- #1
coldsteel
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1.A piece of ice falls on a frozen lake and breaks up into three pieces which go off in the directions shown in the diagram below. The mass of the bigger piece is 4 kg and it moves with a speed of 4 m/s straight down, If the two smaller pieces are 2 kg each and break off at 45 degrees each. What would be their speed right after the breakup?
2. momentum initial = momentum final.
Pi=Pf[
M*V+M*V=M*V+M*V
3. I think I need to find the x and y compenents of the smaller 2kg piece, but I don't know how to start because the bigger piece is at 90 degrees. this would make the x compenent 0 right? if i solve for the y direction... M*V+M*V=0 would I take half of the mass of the big ice chunk becuase it splits evenly? I used 4(2)+2(V)=0 to get a y compenent of 4. then use trig to get the vector velocity which I got to = 5.7 m/s. Is this right?
2. momentum initial = momentum final.
Pi=Pf[
M*V+M*V=M*V+M*V
3. I think I need to find the x and y compenents of the smaller 2kg piece, but I don't know how to start because the bigger piece is at 90 degrees. this would make the x compenent 0 right? if i solve for the y direction... M*V+M*V=0 would I take half of the mass of the big ice chunk becuase it splits evenly? I used 4(2)+2(V)=0 to get a y compenent of 4. then use trig to get the vector velocity which I got to = 5.7 m/s. Is this right?
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