Recent content by xcutexboax

Oh i finally understand... u took the capacitor like a circuit which contatins other "capacitors". Marvellous... Okie thanks for the tip.

If I was referring to the formula C=k*epsilon*A/d where k is the dielectric constant of the material, how does finding the potential change the above expression? I mean if a capacitor can contain like 3 dielectric materials of different k, how does it affect the above expression/formula? =)

Is q=1.60 x 10^-19? Is there a diagram dictating whether the electron is moving in a downward motion?

Hey Guys, I was just doing a question on capacitance and i was wondering since capacitance is usually determined by a fixed formula which is dependent on the di electric material that is contained within a capacitor.. However it struck me that a capacitor does not neccesarily contain...

Ehh yupz...i agree tat it is 0.11196 degrees, but in fact the ans shd be 0.0925 degrees, my mistake for that 6.43... i found out that the angle of deviation is given by a formula: \phi= \frac {\Omega ^2 R \sin \lambda \cos \lambda}{g - \Omega ^2 R \cos^2 \lambda} , where \lambda is the...

Ok based on ur equation, when i subs in all the values of the question: \tan \phi = 0.001959 \phi = 6.43 \deg ---> which is still considerably bigger Actual ans is 0.0925 deg.. Is there any link u can establish with ur equation and the 2 equations i gave you?

I am totally confused by you now that u have introduced the dot product and u oni started with an acceleration vector... Oh mAn... Sorry to bother u... can u Show me at least half of the full working towards getting the deviation...

Hmmm sorry but how do u do that... i jus found out that the 2 equations to resolve the three vectors into their vertical and horizontal components are: \T \cos \phi + m \Omega ^2 R \cos^2 \theta = mg ---> vertical forces \T \sin \phi = m \Omega ^2 R \cos \theta \sin \theta ---->...

I understand that u have resolved the components into the horizontal and vertical axis, but still how do u apply this equation to get the deviation with tension unknown... although it would be canceled eventually... Any more takers?

Hi Guys, I tried drawing a free body diagram, But the term 34.5 north latitude is getting on my nerves... the closest feeling i got wat it meant was the angle made between the Weight of the bob(line of action drawn Diagonally) and the horizontal. Q. A plumb bob does not hang exactly...

Yeah THANKS ThAnks Dude... i see v*dv/dx is actually dx/dt * dv/dx =a Hmmm Nice one.. yeah managed to find a reason to integrate the equation wif no worries... and for the 2nd question i reckon that i could find out the value of x and integrate Fk to get work done then equate it to 1/2mv^2...

Kinetic Friction ! undefined Ok guYS, Really need help for this... i have been staring at this question blankly... The ONly solution i came up was to integrate the net acceleration with respect to x. But i what do u get when u integrate acceleration... the answers for part a is 4 m and...

Finally Solved it... Woooh... thanks i finally solve it... an additional part of the question:: Consider that when the block comes to rest, the change in gravitational potential energy is converted to the elastic potential energy of the spring. However, there is still a net force exerted on...

Springy question... undefined Hi Guys... came across this qns...may seem quite simple but it is actually quite tricky. A Block of mass m=1.00kg situated on an incline at an angle of 43.0 is connected to a spring of negligible mass having a spring constant of 100N/m. the pulley and the...