Recent content by WCU

so (0.605m/s^2)/(9.80m/s^2)=u=0.0617, which happens ot be the answer i was looking for. thankyou so much

I thought m = mass... i need the coefficient of friction (u), and i don't have F, Fn, or m ... what units do i use? i feel like the answer is right in front of me and I'm just too blind to see it

thanks for the help, the formula makes sense, sorta, but i was never taught how to get the normal force without the mass, so I'm still lost, but not as lost i do know the answer is 0.0617 ... i just don't know how to get there ...

multiply the mass by gravity, but remember that gravity will be straight down and the normal force is perpendicular to the block, so use a net force diagram to sort out the remaining forces ... hope that helps, makes more sense in my head than it does typed, lol

yes, i am aware of that, but the MASS is UNKNOWN if anyone knows an alternate formula (one that doesn't require mass) i would be most grateful thanks for your help...

work=F(average)*(cos theta)*distance friction=coefficient of friction * Normal force gravity is always 9.80m/s^2 on earth

ok, i have a problem and w/o a given mass i am lost on how to solve it. "What is the coefficient of kinetic friction between the ice and the puck in the problem above?" problem above states, "A Carolina Hurricanes player hits a puck with his hockey stick during a practice, giving the puck...