Recent content by Sullivan

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    I've been staring at this Newtons first law assignment for hours

    So unless I am mistaken, the forces acting on point B are the tension force between point B and the left wall acting to the left, the tension force between the ceiling and point B acting at a 35 degree angle from horizontal, and then a force from T2 along the y-axis and a force of acting on the...
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    I've been staring at this Newtons first law assignment for hours

    Awesome! Thanks for the help. I really appreciate it. So does this then mean that that T4*Sin35 - 80 = 0 as well then? Or is it T4*Sin35 - 80 - T2 Sin65 = 0 ? (so therefore T4*Sin35 - 160 = 0 ?)
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    I've been staring at this Newtons first law assignment for hours

    Thanks for the reply man! So Is this line of thinking correct then? because T2*cos(65°) - T1 = 0 T2 = T1/cos(65°) ? Then you can sub this into the equation T2*sin(65°) - 80.0N = 0 to get T1/cos(65°) * Sin(65°) = 80.0N ? which gives you T1 = 37.3 N?
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    I've been staring at this Newtons first law assignment for hours

    And I'm starting to feel kind of dumb here... here is the picture to go along with the question Question: Draw a free-body diagram for Point A, showing all the forces acting at A. Resolve the vectors into components, where necessary. Using the first condition of equilibrium, solve...
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    Could someone check my work on this vector assignment question?

    Would anyone willing to check my work on this vector question? I have an assignment due in a few days and was just wondering if someone could look over one of the questions from this assignment and see if I've done it correctly, as I still don't feel entirely confident with this yet. So the...
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    How Is Average Velocity Calculated in Multi-Stage Vector Displacements?

    Right! Thank you very much. I was using total distance rather than displacement wasn't I!
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    How Is Average Velocity Calculated in Multi-Stage Vector Displacements?

    You go for a short walk traveling in three stages. The first displacement is 58.5 m 20.0 degrees east of north. The second displacement is 78.0 m 40.0 degrees south of east. Finally you go 99.0 m 17.0 degrees north of west. The answer I got was 36.9 m, 66.2 degrees north of west,which is...
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    Having trouble finding equation of one question.

    Ah. That's right. I think I input my fields wrong in my calculator. Yikes! I tried again and got 52 myself. Yay! It's quite a good feeling when you get something right. Even though I received lots of help. Thanks again for helping me and the welcome to the forum!
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    Having trouble finding equation of one question.

    That looks like a language very well worth learning. Thanks for introducing it to me. I'll do some reading when I'm done this assignment :] Thanks for spotting my error. So I manipulated the v(truck) * t = v initial (car) * t + 1/2 a * t^2 and got 2 * (v (truck) - v initial (car)) / a = t...
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    Having trouble finding equation of one question.

    Thank you very much for the warm welcome! I'm dedicated to getting an A in this course, so your help is really appreciated. I try my best to figure things out on my own but sometimes I have to ask for help. So... If I understand correctly, since the displacement and time will be the same...
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    Having trouble finding equation of one question.

    Have a very basic physics assignment due tomorrow, and am having trouble finding out an equation for one question. Here is the problem. I'm sorry it's so basic. I've never done physics in my life. I find it beautiful and fascinating, but I am just starting out. I'd love if someone could give...
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