Recent content by Smusko

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    Distance traveled of a ball dropped in water.

    I am sooooo stupid it's almost depressing. Thank you.
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    Distance traveled of a ball dropped in water.

    When you integrate that, what happes with v? v=0.9gt - cs? since ds/dt = v. It feels so wrong. Or do you treat v as a constant and v=0.9gt - cst? That also feels wrong.
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    Distance traveled of a ball dropped in water.

    Homework Statement A steel ball is released at the surface of the ocean and it takes 64 minutes for it to hit the bottom. The balls downward acceleration is a=0.9g-cv where g=9.82 m/s2 and c = 3.02s-1 and v is the speed. What is the depth of the ocean where the ball was released? Homework...
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    Integrating zdS on a Sphere Centered at Origin

    Dang, thought. Missed the ********* **** **** minus sign. I got sqrt(1-Sin2(t)) because (dz/dt) = -aSin(t). Thanks.
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    Order and harmony vs disorder and chaos.

    This is image is representative on how we think the universe looks on the largest scales. [PLAIN]http://upload.wikimedia.org/wikipedia/en/c/c0/Local_galaxy_filaments_2.gif from http://en.wikipedia.org/wiki/Galaxy_filament Looks pretty chaotic.
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    Uncovering the Mystery: The Science Behind White Light and the Sun's Spectrum

    I do not officially know what I'm talking about, but here goes. Maybe theoretically they don't cover every possible infinitesimal change in frequency, but enough to show us that it follows a mathematically smooth probability curve. And when you get the spectrum of a star it comes with a...
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    Integrating zdS on a Sphere Centered at Origin

    I have checked with Wolfram on all the derivatives and integrals. The dS must be equal to a*cos(t)dt and if it is like you say that you put z=a*cos(t) and integrate from 0 to pi/2 then the integral should look like this: a2*Integral(cos2(t))dt = a2((t/2) + (1/4)*sin(2t)) Evaluated from 0 to...
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    Integrating zdS on a Sphere Centered at Origin

    Yeah, helps allot. I have done it that way and failed but I have a knack for making stupid tiny mistakes, like forgetting a minus sign or something. So Il try again. It is nice to know that this stuff is not completely beyond me. :)
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    Integrating zdS on a Sphere Centered at Origin

    I will denote vectors in bold. Homework Statement Show that the curve C given by r=a*Cos(t)Sin(t)i+a*Sin2(t)j+a*Cos(t)k ( 0=<t=<pi/2 ) lies on a sphere centred at the origin. Find \int zdS under C *edit* There is a huge gap here and the equation has dissapered for me. But...
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    Change of variable in triple integrals

    Of course. How stupid of me. I think I have solved it now. I tried again with the new limit and failed, but then I noticed that I by mistake took the square of something that should not be squared. When I correct that mistake it should work out. The source of error in these calculations are...
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    Change of variable in triple integrals

    Ahhhhhh. Now I see... I think. How do I do to form an expression for w then? Or get its limit.
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    Change of variable in triple integrals

    Actually the height is dependent on t. It is a cylinder and R and theta only decides the area of the circle. So that can't be what's wrong. What I'm not 100 percent sure of is the limit.
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    Change of variable in triple integrals

    You are right. I'l check into that. Thanks.
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    Change of variable in triple integrals

    Thanks, you are right. a and b are supposed to be squared in the problem statement. I'll edit it right away.
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    Change of variable in triple integrals

    Homework Statement Solve for the volume above the xy-plane and below the paraboloid z=1-x2/a2-y2/b2 I have gotten an answer that is close to the correct one, but I can't figure out where I am wrong. Homework Equations Solution: Volume is = ab\pi/2 The Attempt at a Solution...
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