Homework Statement
Solve the following equation for P_{1} and P_{2}
Homework Equations
7.0+0.004P_{1}-\lambda(1-0.0004P_{1})=0
7.0+0.004P_{2}-\lambda=0
P_{1}+P_{2}-500-0.0002P_{1}^{2}=0The Attempt at a Solution
I am having some issues on ways to solve this problem. I guess the main point I am...
Thanks all for the replies. I think I have an idea on how to solve the problem with all the hints given. I will not post the solution once I do come to a solution. Thanks again!
Homework Statement
Homework Equations
The area of a circle:
A_c = \pi r^{2}
The Attempt at a Solution
I know that the diameter of the oval shape is 10m since the problem says that it touches the circumference of the center of each circle. I am not sure how to approach the problem...
Thanks tiny-tim. After some research, looks like this is a parametric equation. Since it has cosines and sines, it will most likely be a circle or ellipse from 0<=x<=2\pi.
I will try to solve this and post the solution when done. Thanks again!
Homework Statement
The x and y coordinates of a particle moving in the x-y plane are x=8sin(t) and y=6cos(t). What is the equation of the path of the particle?
Homework Equations
m=\frac{y_2-y_1}{x_2-x_1}
y-y_1=m(x-x_1)
The Attempt at a Solution
I am stuck on how to approach this...
Thanks guys! I finally solved it and got a better understanding of the problem.
Attached is the solution I created in word when trying to solve this problem. Thanks again for everyone's help.
Thanks pongo. I drew it out and understand why my thinking was incorrect on trying to subtract the whole circle.
So I drew it out:
Now I am confused on how to continue to approach this problem. I am not sure if the the portion of (B) is exactly a half circle, which I cannot assume given...
Thanks for the reply pongo38. I might be confusing myself. If I take area of the whole circle and subtract it with the area of the triangle, won't that give me the area of the smaller circle?
Thanks. I researched this and it looks like I can use the SAS (Side Angle Side) formula to get the area of this triangle. That formula is:
A=\frac{1}{2}ab\sin C
Which, for my problem, is equal to:
A_t = \frac{1}{2}(7)(7)\sin 150\degree
A_t = \frac{1}{2}(49)(0.5)
A_t = \frac{49}{4}
Now...
Hi all, I am having an issue trying to solve the following problem
Homework Statement
I know that the radius of the circle is 7 and the angle of the segment is 150°
Homework Equations
Area of a circle: A = \pi{r}^2
Area of the sector of the circle: A = \frac{n}{360}\pi r^{2}
Area...
Great. I think I got it. Since this equation is in the form of:
x=y^{2}
it is a parabola with the general equation of x = a(y-k)^{2} + h. a = 1 and k = 0 in this case. The focus point for a parabola in this form is at (h+p, k) And p = \frac{1}{4a}. Therefore, since a = 1, p=\frac{1}{4}...