So I can write Patm hinitial = P2 (0.25-h) where h is the heigh of compressed air. Me doubt is what is hinitial? Can I Convert the 75cm Hg to cm of air?
NEW
Kuruman thank you for your answer. h1 and h2 are the length of left and right arm respectively. So, how can I solve the problem with ideal gas law? thank you
Homework Statement
A J-shaped tube has an uniform cross section and it contains air to atmosphere pression of 75 cmo of Hg. It is pours mercury in the right arm, this Compress the closed air in the left arm. Which is the heigh of the mercury's column in left arm when the right arm is full of...
Homework Statement
A rectangular weir (Cd = 0.623) thin crest without lateral contraction of 1 meter in length and a triangular weir (theta = 90 °) are located on the same channel. If the apex of the triangular weir (Cd = 0.593) is 0.15 meters below the crest of the rectangular weir and...
I think I understand, but there are some exercises in which is valid to take the zero down or away from the element considered. For example in this exercise (strain energy) and I only integrate in the real part of the element. So when will know whether it is valid or not take away the element...
Homework Statement
A deposit of 20 feet long and 10 feet high, has a width of 8 feet at the bottom and 18 feet at the top. In the bottom is an orifice an area of 24 in2 and discharge coefficient of 0.60. If the tank is full calculate the time required for the lower level 6 feet. Consider full...
Homework Statement
In the figure are the dimensions, and the question is the time in which the take will empty
Area of orifice 1 cm2
Discharge coefficient: 0.447
Gravity 10 m/s2
Homework Equations
[/B]
Area of surface = 8x = 8 (2 H) = 16H
The Attempt at a Solution .
The red lines are the...
Homework Statement
Calculate "H"
Homework Equations
Bernoulli
Manometry
The Attempt at a Solution
I have calculated that Q=0.06723 m^3 /s
If I apply Bernoulli in the surface of the tank A and in out of the pipe, I have: H =(velocity in the final part of the pipe^2)/(2g). I have assumed that...