A solid sphere rolls without slipping down a ramp that is at an angle of 32 above horizontal. The magnitude of the acceleration of the center of mass of the sphere as it rolls down the ramp is?
sum of torques = I(alpha)
rmgsin32 = (2/5)mr^2(a_tan/r)
the radii drop out as one would...
A diving board of length 3.00 m is supported at a point a distance 1.00 m from the end, and a diver weighing 550 N stands at the free end. The diving board is of uniform cross section and weighs 255 N. Find the force at the end that is held down.
In part a, I found the normal force at the...
How is the woman mr^2. Is she considered a hollow cylinder? If so, then, I have to add the momentum of the disk itself and then the momentum of her separately? How do account for the fact that she is on the disk, such that the disk is heavier with her on it?
A woman with a mass of 45.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.490 rev/s about an axis through its center. The disk has a mass of 120 kg and a radius of 4.50 m. Calculate the magnitude of the total angular momentum of the woman-plus-disk...
A hollow, spherical shell with mass 1.95 rolls without slipping down a slope angled at 30.0. Find the minimum coefficient of friction needed to prevent slipping.
I have already calculated the acceleration of the sphere and the magnitude of the friction force on the sphere in previous parts...
A thin, uniform rod is bent into a square of side length "a". If the total mass is M, find the moment of inertia about an axis through the center and perpendicular to the plane of the square. Use the parallel-axis theorem.
According to Parallel Axis theorem:
I = I(cm) + Md^2
The...
Ok, this makes sense. But they want the answer in terms of M and L. When I substitute my expression for gamma after integration, I get
[(4LMX^3)-(6MX^4)]/(6L^2)
There's no way I can see to get rid of X, so now I'm stuck...again.
A slender rod with length L has a mass per unit length that varies with distance from the left-hand end, where x=0, according to dm/dx = (gamma)x, where (gamma) has units of kg/m^2.
I calculated the total mass of the rod by integrating. I got
M = 0.5(gamma)L^2
In the second part I...
A projectile of mass 20.2 kg is fired at an angle of 65.0 above the horizontal and with a speed of 84.0 m/s. At the highest point of its trajectory the projectile explodes into two fragments with equal mass, one of which falls vertically with zero initial speed. You can ignore air resistance...
well, i suppose it can't. So this is a trick question, and the canoe doesn't move at all? According to Newton, however, equal and opposite and all that jazz. Shouldnt friction between the woman and the canoe cause the canoe to move opposite to her motion since the water is essentially...
A 45.0-kg woman stands up in a 60.0-kg canoe of length 5.00 m. She walks from a point 1.00 m from one end to a point 1.00 m from the other end. If you ignore resistance to motion of the canoe in the water, how far does the canoe move during this process?
At first I thought that the canoe...