Recent content by mxtiger67

I guess what I'm asking is, where is the power loss, where does it go?

My question is why the power efficiency % goes down with Voltage in step down transformers. The #of coils is less, therefore internal resistance is less too. Why the loss of efficiency in power? I hope someone can help

sin \theta = -(-2 \frac{W_{incline}}{W_{hanging}} ) +or - square root of (2 \frac{W_{incline}}{W_{hanging}} )^2 - 4(\frac{W_{incline}^2}{W_{hanging}^2} + \frac{W_{incline}^2}{W_{hanging}^2} \mu^2)(1 - \frac{W_{incline}^2}{W_{hanging}^2} \mu^2)/(2(\frac{W_{incline}^2}{W_{hanging}^2} +...

ok, then my mistake is somewhere where I solve for sin(angle) Ax^2 + Bx + C = 0, I get -(-5.78)+or-sqrroot(5.78*2-4(11.55)(-2.2))/(2(11.55)) so I end up with sin(angle)=.752 or -.25 did I put numbers wrong in the equation? because I still get 50 and -15? where am I wrong? and after I...

So basically from the angles that you came up with, such angle doesn't exist. I did the math a bit differently and my angles came out differently, but still are not working. I have 45=130sin(angle)+80.6cos(angle) divide by 45 1=2.89sin(angle)+1.79cos(angle) now put 2.89sin(angle) on the...

Yeah and both of those posts are just rewritten formulas of what I've already wrote. I'm having problem with the math trying to figure the formula out. I keep coming up with angle of 48.7 degrees, but when I try to sub it and check, it's coming out wrong.

How do I find Tension? Is it just the weight of the second block, 45Newtons?

You have a block on the incline plane 130 Newtons and it's attached by a rope through a "frictionless" pulley to another block of 45 Newtons hanging of the side of a plane. The question is what angle pheida has to be in order for a 130 Newtons block to start sliding up the plane (not...