- #1
mxtiger67
- 8
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You have a block on the incline plane 130 Newtons and it's attached by a rope through a "frictionless" pulley to another block of 45 Newtons hanging of the side of a plane. The question is what angle pheida has to be in order for a 130 Newtons block to start sliding up the plane (not accelerating) when coefficient of friction is 0.62.
I think the equation starts like this:
45=130*sinO + 0.62*130*cosO
I've tried solving for it, but it's not coming out.
Can anyone help!
I think the equation starts like this:
45=130*sinO + 0.62*130*cosO
I've tried solving for it, but it's not coming out.
Can anyone help!