Well in the the bottom half I would assume you would have to use u-subsitution but I don't believe the question is asking me to solve the bottom until I prove the top is = b/2?
So we know that the initial intertia of the merry go round is 250 kg m^2 and its angular speed is 10 rpm. MGRs angular momentum would be L=Iw=250(10)=2500kg m^2 rpm.
We know the mass if the child is 25kg, and the child's linear velocity is 6m/s. We convert linear to angular w= v/r = 6/2 =...
Hmmm... I was thinking of a function like f(x)= 4x-8/x-2 = 4(x-2)/x-2 = 4, that would make a hole at x=2.
But would also make f(2) = 4 ? Would it be safe to assume since there is a hole at (2,4) , it is undefined therefore f(2) does not equal 4 ?
So I'm guessing we need our end unit to be in MPG?
a) walking
( 220 kcal/ 1 hr )⋅ ( 1hr / 3 mile ) = 73 .3 kcal/mi⋅⋅
(73 .3 kcal/ 1 mile) ⋅ (4,186 J/1 kcal) = 3,06833.8 J/mi
(1.30 x 10^8 J/ 1 gal)(1 mile / 3,06833.8 J) = 423.68 MPG
b) bicycling
Not sure as it says,"...when riding at 10.0...