Recent content by Mustard

  1. M

    Comp Sci How Does a Boolean Variable Impact Program Functionality in C++?

    #include <iostream> #include <string> #include<iomanip> //prototypes double gettingInfo(double&, double&, double&, bool&, char&); double errorChecking(double&); double calculatingPrice(double&, double&, double&, bool&); double printingReciept(double&, double&, double&,double&); using namespace...
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    Integral proof and then use the proof to solve a 2nd integral

    Oh , I'm stuck again. Am I doing it right si far ? :/ I'm sorry it's just confusing to me.
  3. M

    Integral proof and then use the proof to solve a 2nd integral

    Well in the the bottom half I would assume you would have to use u-subsitution but I don't believe the question is asking me to solve the bottom until I prove the top is = b/2?
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    Conservation of Angular Momentum -- Child jumping onto a Merry-Go-Round

    So we know that the initial intertia of the merry go round is 250 kg m^2 and its angular speed is 10 rpm. MGRs angular momentum would be L=Iw=250(10)=2500kg m^2 rpm. We know the mass if the child is 25kg, and the child's linear velocity is 6m/s. We convert linear to angular w= v/r = 6/2 =...
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    Question Error? (epsilon-delta proof of a limit)

    I can not follow this mathematically. I am guessing one of the signs is incorrect? Can anyone verify ?
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    Finding a function given a limit and restriction

    Do you mean like a piece wise function ?
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    Finding a function given a limit and restriction

    Hmmm... I was thinking of a function like f(x)= 4x-8/x-2 = 4(x-2)/x-2 = 4, that would make a hole at x=2. But would also make f(2) = 4 ? Would it be safe to assume since there is a hole at (2,4) , it is undefined therefore f(2) does not equal 4 ?
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    Finding a function given a limit and restriction

    Not sure how to go about this. Would relying on a hole or asymptote work?
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    Can Two Protons Have the Same Speed After an Elastic Collision?

    m1v1i + m2v2i = (m1+m2)vf (1.67 × 10^-27)v1i = (1.67 × 10^-27 + 1.67 × 10^-27) vf (1.67 × 10^-27/3.34 × 10^-27)v1i = (3.34 × 10^-27/3.34 × 10^-27) vf (1.67 × 10^-27/3.34 × 10^-27)v1i = vf (0.5)(v1i) = vf not sure what to do from here nor if I'm in the correct path ?
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    Conversion to fuel economy in equivalent MPG using kcal/h and mi/h

    So I can ignore the above statement as the will basically cancel out ?
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    Conversion to fuel economy in equivalent MPG using kcal/h and mi/h

    So I'm guessing we need our end unit to be in MPG? a) walking ( 220 kcal/ 1 hr )⋅ ( 1hr / 3 mile ) = 73 .3 kcal/mi⋅⋅ (73 .3 kcal/ 1 mile) ⋅ (4,186 J/1 kcal) = 3,06833.8 J/mi (1.30 x 10^8 J/ 1 gal)(1 mile / 3,06833.8 J) = 423.68 MPG b) bicycling Not sure as it says,"...when riding at 10.0...
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