A rigid T consists of a long rod glued perpendicular to another rod of length l that is pivoted about the
origin. The T rotates around in a horizontal plane with constant frequency ω. A mass m is free to slide along the long
rod and is connected to the intersection of the rods by a spring...
Homework Statement
A particle is confined to move on the surface of a circular cone with its axis
on the vertical z axis, vertex at origin (pointing down), and half-angle α(alpha)
a) write down the lagrangian in terms of spherical coordinates r and ø (phi)
Homework Equations...
Ok, so I've rewritten the energy conservation formula and what it comes down to is:
m1v1xi2= m1v1yf2+m2v2xf2+m2v2yf2
with some substitution with my known quantities i.e mass and m2v2xf=140/25
i get 2016= 7kgv1yf2+25v2yf2
which i solve in terms of v1yf and sub into -m2v2fy=m1v1yf...
Homework Statement
In deep space a 7.0 kg rubber ball moving along the x-axis with a speed of 20 m/s collides ELASTICALLY with another ball of mass = 25 kg. After the collision the 7.0kg rubber ball's velocity is directed in the positive y axis. Find the final speed of the 7 kg ball, as well...
When two objects move under the influence of their mutual force alone, we can treat the relative motion as a one-particle system of mass μ=m1m2/(m1+m2). An object of mass m2and charge -e orbits an object of mass m1 and charge +Ze. By appropriate substitutions into formulas given in the chapter...
And just incase anyone else looks at this or needs help the correct equations are:
A'(30)= -λA0e(-30λ)
A'(t0)= A'(0) = -λA0e(0)= -λA0
(Because e0=1 of course)
And we know that A'(30)/ A'(0) = 0.125
Thus the ratio of A'(30)/ A'(0) = e(-30λ)= 0.125
Taking ln of both sides and...
hahah oh wow, so you still have to solve for your lambda first. I thought there was going to be some way to directly solve for t1/2 without first solving for lambda haha.
if that's the case i could of just as easily set up: 0.125A0=A0e(-λt)
at t=30hrs haha this yields the same result...
Yes you're right that doesn't make sence... So for the rates as you said before i must use the derivative of the function
d/dt A(t)= -λA0e(-λt)
So:
A'(30hr)= -λA0e(-30hrλ)=0.125
and the other? Is it just
A'(t0)= -λA0e(-λt0)=1 ?
You'll have to forgive me if i don't immedietly see...
Ok sure, so the derivative of A(t)=A0e(-λt) is
A'(t)= -λA0e(-λt) correct?
and you propose to set this equal to the 0.875/30 hours? Such that:
0.875/30hrs= -λA0e(-λt)
However you would have three unknowns still? I think I am just missing somthing small. But i just don't see how you...
Hey so in regards to this how will taking the derivative help you? I also considered both her methods and realized the one assumed a linear relationship. Would you take the derivative and set it = 1/2? and even so you have more than one unknown variable...