Here's a picture. Unfortunately, going active will not be an option because supplying power to the op-amp will not be feasible.
I'm unfamiliar with switching out components like you mentioned. Can you elaborate?The resistor at the end of the circuit is simulating the load, and so can't be changed
I just recently built a low-pass butterworth filter with a cutoff of 50Hz. When I looked to purchase the parts, I noticed that each inductor had a resistance of several hundred ohms. I put this information into my simulator program and the result was something that looks nothing like the...
I am designing a 5-pole low-pass butterworth filter to have a cutoff frequency of ~50 Hz. It has a source impedance of ~1 Ohm, and a load impedance of ~50 Ohm (The load impedance can be changed around if that will help later). Because of these, I am using the "T" configuration. I used the table...