The 20-kg sphere, attached to a spring of stiffness 500 N/m
is released from an un-stretched position of the spring, as
shown in the figure. Determine the velocity of the
block “A” of mass 10 kg, at the instant the ball has fallen
25 cm. A roller mechanism keeps the spring in a vertical...
so using v = u + at:
v = 1m/s + .1(5)
v = 1.5 m/s
now I need a. i believe i need to find radial and tangential a?
so i have a = vdot
so a_r = .1 m/s^2
but how do I get the acceleration that is based on the curve y = .5x^2?
I have to do these 2 problems for homework, but I can't figure them out. Any help would be appreciated.
1. The motorcycle is traveling at 1m/s when it is at A(the origin). If the speed is then increased at \dot{V} = .1 m/s^2, determine its speed and acceleration at the instant t = 5 seconds...