Yes, I see. I think I did intend to put an input in there. So let me re-formulate my equation as:
y''(t)+y'(t)+y(t)+C = u(t)
where u(t) is an input. If I take the laplace of both sides I get
s2Y(s)+sY(s)+Y(s)+(C/s) = U(s).
But now I have a term on the left side that doesn't have Y(s) in it, so I...
I have a differential equation of the form y''(t)+y'(t)+y(t)+C = 0. I think this implies that there are non-zero initial conditions. Is it possible to write a transfer function for this system?
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