Hi,
Please help me on this. I do not how to start on this integration, so i simply apply basic integration rule. Usually, there is a formulas sheet for me to convert this alike question to trigo form(after integrate) but this one seem different.
edited: y^2 is const
The Attempt at a Solution...
sry for the late reply...
1. for example, if the system give destructive result, i should sub in (m + 1/2)\lambdan into \Delta at the third line of equation ?
2. and you mentioned the 2t is relate to the wavelength, then we actually can use that to find the wavelength entered into the thin...
Homework Statement
Hi guys,
I tried google for it but no avail so i seek for your help. I have a impulse function x[n] = [1 2 3 4] for n= -4 to 0
The Attempt at a Solution
what does the 1 2 3 4 inside the bracket mean? at n = -3, there is a amplitude of 2?
Thank you.
Hi guys,
i have problem with Interference in Thin Films, i tried worked the solution not sure it is correct. Hope someone can help me check? Also there is some part on the topic i don't quite follow, 2t is the extra distance traveled inside the film, then is 2t is also rough estimate of...
If 1 is integrated, we get t and then sub in the boundary value the answer still 0?
here the actual g(t) suppose to be g(t) = cos(2\pif0t) - jsin(2\pif0t).
Hi again,
I have a problem regarding improper integration.
Homework Statement
Refer to the image. I tried to solve and got zero for the answer. Is that correct? I refer to my actual problem it seem like it don't won't this way...
Thanks
Hi,
i have a problem with integration a function with a unit step function.
Homework Statement
Given,
Refer to the image, i dun understand is that u(t) is equal to 1 from a definite integration from -\infty to \infty since u(t)=1 from -\infty to 0 and u(t)=0 from 0 to \infty...
Homework Statement
Prove: 2n + 1 < 2n , with n >= 3Homework Equations
The Attempt at a Solution
2 (3) + 1 = 7 and 23 = 8.
So 2 (3) + 1 < 23.
Thus the inequality holds with n = 3:
Suppose the inequality holds with n = k
Then 2k+ 1 < 2k:
So 2k + 1 + 2 < 2k + 2
2k + 3 < 2k + 2k
2k + 3 < 2(2k)
2...