Recent content by jevanuD

  1. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    We've only stated 2 angles 90 and 270, is it either of those?
  2. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    wow I am lost there, but i would then solve this equation?
  3. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    from that I'm seeing 3 points marked, which is 3 solutions?
  4. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    Are you saying I should plot my 2 solutions into: {0}^{0}\le\theta\le360^{0}
  5. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    \left(3x+1\right)\left(x-1\right)
  6. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    \sin\left({\theta}\right)\left(3\sin\left({\theta}\right)-3\right)=0
  7. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    3\sin\left({\theta}\right){}^{2}=3?
  8. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    Yes correct, I've made my substitutions to prove that question A is indeed true, however i am not sure how to start "B"
  9. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

    I am aware that $\tan(x) = \frac{\sin(x)}{\cos(x)}$ and the other fundamental which is $1-\cos ^2(x)=\sin ^2(x)$ i just need some clarity on how its proven.x
  10. J

    MHB Is \(\theta=360^\circ-\beta\) When \(\sin(\beta)=\frac{1}{3}\)?

  11. J

    MHB How do you calculate the area and arc length of region ABCD using given values?

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